We have proven that the trigonometric identity [(tan θ)/(1 - cot θ)] + [(cot θ)/(1 - tan θ)] equals 1 + (secθ * cosec θ)
<h3>How to solve Trigonometric Identities?</h3>
We want to prove the trigonometric identity;
[(tan θ)/(1 - cot θ)] + [(cot θ)/(1 - tan θ)] = 1 + sec θ
The left hand side can be expressed as;
[(tan θ)/(1 - (1/tan θ)] + [(1/tan θ)/(1 - tan θ)]
⇒ [tan²θ/(tanθ - 1)] - [1/(tan θ(tanθ - 1)]
Taking the LCM and multiplying gives;
(tan³θ - 1)/(tanθ(tanθ - 1))
This can also be expressed as;
(tan³θ - 1³)/(tanθ(tanθ - 1))
By expansion of algebra this gives;
[(tanθ - 1)(tan²θ + tanθ.1 + 1²)]/[tanθ(tanθ(tanθ - 1))]
Solving Further gives;
(sec²θ + tanθ)/tanθ
⇒ sec²θ * cotθ + 1
⇒ (1/cos²θ * cos θ/sin θ) + 1
⇒ (1/cos θ * 1/sin θ) + 1
⇒ 1 + (secθ * cosec θ)
Read more about Trigonometric Identities at; brainly.com/question/7331447
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A. correct as it is
B. 5, 4, 3, 0
Answer:
2
Step-by-step explanation:
The trick here is to reduce each of the bases to lowest form first
To get the Total amount upon investment for the compound interest, plug in the value of x into the given expression bellow
<em>A = 9,000.00(1 + x/100)^(4)</em>
Given data
Principal = $9000
Time = 4 years
Rate = x% per annum
<h3>Solution</h3>
First, convert R as a percent to r as a decimal
r = x/100
r = x/100
Then solve the equation for A
A = P(1 + x/100)^t
A = 9,000.00(1 + x/100)^(4)
A = 9,000.00(1 + x/100)^(4)
The total amount accrued, principal plus interest, with compound interest on a principal of $9,000.00 at a rate of x% per year.
Learn more about compound interest here:
brainly.com/question/24924853
The value of h(f(x)) would just be x. That is the line y = x which is the line that functions are reflected in to find the inverse.
