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Kobotan [32]
3 years ago
12

5,049 +48=105

Mathematics
1 answer:
Alborosie3 years ago
4 0
<h2>Solution (a) :-</h2>

Let the cost of the less expensive comic book be x .

Then :-

1284 - 11x = x

Using this equation , we can find the cost of the less expensive comic book .

Price of the less expensive book :-

1284 - 11x = x

11x + x = 1284

12x = 1284

x =  \frac{1284}{12}

x = 107

Cost of the less expensive book is 107 .

Therefore , the epice of the less expensive book = $ 107 .

<h2>Solution (b) :-</h2>

Cost of the more expensive book = 11x

Which means :-

1284 - x = 11x

11x + x = 1284

12x = 1284

x = 107

11x = 11 \times 107

= 1177

Therefore , the price of the more expensive book = $ 1177 .

You might be interested in
The difference of the degrees of the polynomials p(x) = 3x2y2 + 5xy? - x6 and q(x) = 3x5 - 4x3 + 2 is
svet-max [94.6K]

Answer:

The difference of the degrees of the polynomials p (x) and q (x) is 1.

Step-by-step explanation:

A polynomial function is made up of two or more algebraic terms, such as p (x), p (x, y) or p (x, y, z) and so on.

The polynomial’s degree is the highest exponent or power of the variable in the polynomial function.

The polynomials provided are:

p(x) = 3x^{2}y^{2} + 5xy - x^{6}\\\\q(x) = 3x^{5} - 4x^{3} + 2

The degree of polynomial p (x) is:

\text{deg}\ p (x)=6

The degree of polynomial q (x) is:

\text{deg}\ q (x)=5

The difference of the degrees of the polynomials p (x) and q (x) is:

\text{deg}\ p(x)-\text{deg}\ q(x)=6-5=1

Thus, the difference of the degrees of the polynomials p (x) and q (x) is 1.

6 0
3 years ago
The population of a community is known to increase at a rate proportional to the number of people present at time t. If the popu
Lady bird [3.3K]

Answer:

P(t) = P(0)e^{0.0693t}

Step-by-step explanation:

The population of a community is known to increase at a rate proportional to the number of people present at time t.

This means that the population growth is modeled by the following differential equation:

\frac{dP(t)}{dt} = rP(t)

Which has the following solution:

P(t) = P(0)e^{rt}

In which P(t) is the population after t years, P(0) is the initial population and r is the growth rate.

The population has doubled in 10 years

This means that P(10) = 2P(0). We use this to find r.

P(t) = P(0)e^{rt}

2P(0) = P(0)e^{10r}

e^{10r} = 2

\ln{e^{10r}} = \ln{2}

10r = \ln{2}

r = \frac{\ln{2}}{10}

r = 0.0693

So the equation that will estimate the population of the community in t years is:

P(t) = P(0)e^{0.0693t}

6 0
3 years ago
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0.86 if it is rounded.
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