Given that JKLM is a rhombus and the length of diagonal KM=10 na d JL=24, the perimeter will be found as follows;
the length of one side of the rhombus will be given by Pythagorean theorem, the reason being at the point the diagonals intersect, they form a perpendicular angles;
thus
c^2=a^2+b^2
hence;
c^2=5^2+12^2
c^2=144+25
c^2=169
thus;
c=sqrt169
c=13 units;
thus the perimeter of the rhombus will be:
P=L+L+L+L
P=13+13+13+13
P=52 units
Answer:
$5830.
Explanation:
730-510=220m
220/4=55 dresses made
55*106=$5830
I can answer the first four
1 is 40%
2 is 60
3 is $1.35
4 is 6%
Answer:
75 quarters 25 nickels
Step-by-step explanation:
q=quarters n=nickels
q+n=100 n=100-q
0.25q +0.05(100-q)=20
From now I will multiply by 100 to avoid decimals
25q + 5(100-q)=2000
20q=1500
q=75 n=25
75*0.25= 18.75
25*0.05=1.25
18.75+1.25=20
