The value of c, the constant of the function y = ax² + bx + c, exists -3.
<h3>What is an equation?</h3>
An equation exists as an expression that indicates the relationship between two or more numbers and variables.
Given that: y = ax² + bx + c
At point (4, 21)
21 = a(4²) + 4b + c .......(1)
At point (5, 32)
32 = a(5²) + 5b + c .........(2)
At points (6, 45)
45 = a(6²) + 6b + c .......(3)
Therefore, the value of a = 1, b = 2 and c = -3.
The value of c, the constant of the function y = ax² + bx + c, exists -3.
To learn more about equations refer to:
brainly.com/question/2972832
#SPJ9
Hey there!
Since you probably have better things to do, your answer would be A: π(3)²
To back up my answer, the formula to find the area of a circle is π · R² where R = Radius. In that formula then, you just plug everything in. Since the radius is 3, you would put 3 into the "( )". Finally, just plug the rest of the equation in!
<em>I'm open to any question or comment!</em>
<em>God Bless!</em>
<em>-X8lue83rryX</em>
Now, If the exponent was negative like you asked....
Quotient rule says we can divide 192 and 3 because they are both under the radical. This gives us the square root of 64.
We can also divide x^3 and x to get x^2.
The square root of 64x^2 is 8x
