Answer:
a. 0.76
b. 0.23
c. 0.5
d. p(B/A) is the probability that given that a student has a visa card, they also have a master card
p(A/B) is the probability that given a student has a master card, they also have a visa card
e. 0.35
f. 0.31
Step-by-step explanation:
a. p(AUBUC)= P(A)+P(B)+P(C)-P(AnB)-P(AnC)-P(BnC)+P(AnBnC)
=0.6+0.4+0.2-0.3-0.11-0.1+0.07= 0.76
b. P(AnBnC')= P(AnB)-P(AnBnC)
=0.3-0.07= 0.23
c. P(B/A)= P(AnB)/P(A)
=0.3/O.6= 0.5
e. P((AnB)/C))= P((AnB)nC)/P(C)
=P(AnBnC)/P(C)
=0.07/0.2= 0.35
f. P((AUB)/C)= P((AUB)nC)/P(C)
=(P(AnC) U P(BnC))/P(C)
=(0.11+0.1)/0.2
=0.21/0.2 = 0.31
Answer:
the first number is 2, the second number is 9 :)
Step-by-step explanation:
brainliest? :)
Answer:
f(g(2)) = 4
Step-by-step explanation:
find g(2) then substitute the value obtained into f(x)
locate x = 2 on the x- axis, go vertically up to meet g(x) at (2, 5 )
locate x = 5 on the x- axis, go vertically up to meet f(x) at (5, 4 )
then f(g(2)) = 4
Answer:
43.35 years
Step-by-step explanation:
From the above question, we are to find Time t for compound interest
The formula is given as :
t = ln(A/P) / n[ln(1 + r/n)]
A = $2500
P = Principal = $200
R = 6%
n = Compounding frequency = 1
First, convert R as a percent to r as a decimal
r = R/100
r = 6/100
r = 0.06 per year,
Then, solve the equation for t
t = ln(A/P) / n[ln(1 + r/n)]
t = ln(2,500.00/200.00) / ( 1 × [ln(1 + 0.06/1)] )
t = ln(2,500.00/200.00) / ( 1 × [ln(1 + 0.06)] )
t = 43.346 years
Approximately = 43.35 years
