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Over [174]
3 years ago
9

Find the angle measure in degrees

Mathematics
1 answer:
loris [4]3 years ago
7 0

Answer:

82°

Step-by-step explanation:

By inscribed angle theorem:

m\angle QRP =  \frac{1}{2}  \times 164 \degree \\  \\   \huge \red{ \boxed{\therefore \: m\angle QRP =82 \degree}}

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IceJOKER [234]
The answer is 3/4 because if u count it up it equals 36/48 and then u just have to simplify
3 0
3 years ago
Regular hexagon FGHIJK shares a common shares a common center with square ABCD on a coordinate plane .
timurjin [86]

Answer:

<h3>"The answer is the yellow lines in the attached figure. </h3>

Step-by-step explanation: As shown in the attached figure, regular hexagon FGHIJK and square ABCD shares common centre on the co-ordinate plane and AB || FG.

We are to find the line across which the combined figure will reflect onto itself.

In the attached figure, we see two lines which are yellow in colour. We can easily detect that the figure will be reflected onto itself if these two lines acts as a mirror separately.

Hence these yellow lines are the required lines."

<h3><u>Hope this helps!</u></h3>

6 0
2 years ago
Determine the solution set of (2x - 5)2 = 11.
zhenek [66]
I think what you meant was

(2x - 5)² = 11 -- (1)

Square root both sides of (1), i.e.

√(2x - 5)² = ± √11 -- (2)

From (2), we have

2x - 5 = ± √11 -- (3)

By adding 5 to both sides in (3), we have

2x = 5 ± √11 -- (4)

Divide both sides of (4) by 2, and we obtain

x = (5 ± √11)/2 -- (5)

From (5), the solution set of (1) is

x = (5 + √11)/2, (5 - √11)/2 ...Ans.
8 0
3 years ago
Read 2 more answers
Is y =3/4x +2 And -6x+8y=16 parallel or coincident
Rudiy27

Answer:

parallel

Step-by-step explanation:

y=3/4x+2

Multiply the equation by 8:

8y=6x+16

(8y-6x)=16

and you can clearly see that they're same

4 0
3 years ago
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galben [10]
Across smallest side- smallest angle.
across largest side- largest angle
largest side is AC, so largest angle is B
smallest side is AB, so smallest angle is C
angles from smallest to largest : C, A, B
4 0
3 years ago
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