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zimovet [89]
3 years ago
9

Job A -Sales- offers a base salary of $1,000 per week plus 3% commission on all sales above $3000. Job B -Sales- offers a base s

alary of $1,100 per week plus 2.5% commission on all sales above $3000. The total sales for the week equal $25,000. How much more does Job A pay than Job B?
Mathematics
1 answer:
Ivahew [28]3 years ago
6 0

Answer:

Job A pay <u>$25</u> than Job B.

Step-by-step explanation:

Given:

Job A -Sales- offers a base salary of $1,000 per week plus 3% commission on all sales above $3000.

Job B -Sales- offers a base salary of $1,100 per week plus 2.5% commission on all sales above $3000.

The total sales for the week equal $25,000.

Now, to find how much more money Job A pay than Job B.

Total sales = $25,000.

Job A pay:

Base salary = $1,000.

Base salary plus 3% commission on $25000.

$1000 + 3% of $25000.

= 1000+\frac{3}{100}\times 25000

=1000+0.03\times 25000

=1000+750

=1750.

Job A pay = $1750.

Now,

Job B pay:

Base salary = $1,100.

Base salary plus 2.5% commission on $25000.

$1,100 + 2.5% of $25,000.

=1100+\frac{2.5}{100}\times 25000

=1100+0.025\times 25000

=1100+625

=1725

Job B pay = $1725

So, by deducting the salary of Job B from Job A we get the more amount:

1750-1725\\=25

Therefore, Job A pay $25 than Job B.

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Step-by-step explanation:

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Andy purchased a pair of shoes for $40. They had been discounted 25%. What was the original price of the shoes
natali 33 [55]

Answer:160


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Question 1 of 25
aleksklad [387]
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Assume you have noted the following prices for books and the number of pages that each book contains. Book Pages (x) Price (y) A
belka [17]

Answer:

a) y=0.00991 x +1.042  

b) r^2 = 0.7503^2 = 0.563

c) r=\frac{7(30095)-(4210)(49)}{\sqrt{[7(2595100) -(4210)^2][7(354) -(49)^2]}}=0.7503  

Step-by-step explanation:

Data given

x: 500, 700, 750, 590 , 540, 650, 480

y: 7.00, 7.50 , 9.00, 6.5, 7.50 , 7.0, 4.50

Part a

We want to create a linear model like this :

y = mx +b

Wehre

m=\frac{S_{xy}}{S_{xx}}  

And:  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}  

With these we can find the sums:  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=2595100-\frac{4210^2}{7}=63085.714  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i){n}}=30095-\frac{4210*49}{7}=625  

And the slope would be:  

m=\frac{625}{63085.714}=0.00991  

Nowe we can find the means for x and y like this:  

\bar x= \frac{\sum x_i}{n}=\frac{4210}{7}=601.429  

\bar y= \frac{\sum y_i}{n}=\frac{49}{7}=7  

And we can find the intercept using this:  

b=\bar y -m \bar x=7-(0.00991*601.429)=1.042  

And the line would be:

y=0.00991 x +1.042  

Part b

The correlation coefficient is given by:

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

For our case we have this:

n=7 \sum x = 4210, \sum y = 49, \sum xy = 30095, \sum x^2 =2595100, \sum y^2 =354  

r=\frac{7(30095)-(4210)(49)}{\sqrt{[7(2595100) -(4210)^2][7(354) -(49)^2]}}=0.7503  

The determination coefficient is given by:

r^2 = 0.7503^2 = 0.563

Part c

r=\frac{7(30095)-(4210)(49)}{\sqrt{[7(2595100) -(4210)^2][7(354) -(49)^2]}}=0.7503  

4 0
3 years ago
Two-thirds of the difference between a number and four is six
hodyreva [135]
2/3 times x-4 = 6
thats the answer :) 
7 0
3 years ago
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