Question

A stone is dropped from the edge of a roof, and hits the ground with a velocity of -185 feet per second. How high (in feet) is the roof?

Answer 1

Vf^2 = Vi^2 + 2*a*d Vf = -185 Vi = 0 a = -9.8 so for d

Answer 2

Answer:

The height of the roof is 534.8 feet.

Step-by-step explanation:

Let h be the height of the roof.

We know the formula

$v^2-u^2=2gh$

Since, the stone is dropped from the edge of the roof hence, the initial velocity should be zero. Thus, u = 0

$v^2-0=2gh\\h=\frac{v^2}{2g}$

Now, we have

v = -185 feet per second

g = 32  feet per square second

On substituting these values, we get

$h=\frac{(-185)^2}{2\times 32}\\\\h=534.8$

The height of the roof is 534.8 feet.