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AlekseyPX
3 years ago
11

Write the raito as a fraction simplest from 12 boys and 15 girls​

Mathematics
1 answer:
kiruha [24]3 years ago
3 0

Step-by-step explanation: We can write a ratio using the word "to", using a colon, or using a fraction bar.

Here, since we want our ratio in simplest form,

I would use a fraction bar.

Now, the problem asks us to compare

the number of boys to the number of girls.

We know that there are 12 boys

and we know that there are 15 girls.

So our ratio is 12/15.

However, this can be reduced to 4/5.

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Answer: 21/5

Step-by-step explanation:

6 0
3 years ago
Please help me! I need this answered fast!
zysi [14]

Answer:

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3 0
3 years ago
What expression is equivalent 19/38
Alex
I am not going to tell you the answer but i can tell you how to find it out. First you have to put 19/38 on a paper. Then multipy the numarator and denomanator by the same number on the top and bottom which is called a whole number. 19/38 times 2/2 or 3/3 or 4/4 or anything. Your answer is equivalent to 19/38
4 0
3 years ago
Read 2 more answers
The diameter of a circle is 16 kilometers. Find the area of the circle.
Elden [556K]

The diameter of a circle is 16 kilometers. Then the area of the circle is 201.062 \mathrm{km}^{2}

<u>Solution:</u>

Given that , the diameter of a circle is 16 kilometers  

We have to find the area of the circle .

Radius is half of diameter.

\begin{array}{l}{\text { diameter }=2 \times \text { radius } \rightarrow \text { radius }=\frac{\text {diameter}}{2}} \\\\ {\rightarrow \text { radius }=\frac{16}{2} \rightarrow \text { radius }=8 \text { kilometers. }}\end{array}

<em><u>The area of circle is given as:</u></em>

\begin{array}{l}{\text { area of a circle }=\pi \times r^2 \\ {\text { Area of a circle }=\pi \times 8^{2}=\pi \times 64=64 \times 3.14=201.062}\end{array}

Hence, the area of the circle is 201.062 km^2

4 0
3 years ago
Which of the following expressions is equivalent to -5.4 - (2.1 + 1.8)?
Paul [167]

Answer:

its the first one

Step-by-step explanation:

7 0
3 years ago
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