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AlekseyPX
3 years ago
11

Write the raito as a fraction simplest from 12 boys and 15 girls​

Mathematics
1 answer:
kiruha [24]3 years ago
3 0

Step-by-step explanation: We can write a ratio using the word "to", using a colon, or using a fraction bar.

Here, since we want our ratio in simplest form,

I would use a fraction bar.

Now, the problem asks us to compare

the number of boys to the number of girls.

We know that there are 12 boys

and we know that there are 15 girls.

So our ratio is 12/15.

However, this can be reduced to 4/5.

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The probability of two events that are not mutually exclusive may be calculated using the formula
Nataly [62]

Answer:

7/13

Step-by-step explanation:

P(A or B) = P(A) + P(B) − P(A and B)

P(red or jack) = P(red) + P(jack) − P(red and jack)

P(red or jack) = 26/52 + 4/52 − 2/52

P(red or jack) = 28/52

P(red or jack) = 7/13

7 0
3 years ago
Read 2 more answers
What is the first step when solving the following inequality x+2/-5<4? Group of answer choices A. Add 5 to both sides and DO
LiRa [457]

Assuming we're dealing with \frac{x+2}{-5} < 4, which is the same as writing (x+2)/(-5) < 4, then the answer is choice C.

We multiply both sides by -5 and this will flip the inequality sign.

-------------------------------------

Multiplying or dividing both sides by a negative number flips the inequality sign.

An example would be saying -2x < 10 leads to x > -5

What we can do is divide both sides by -2 and flip the inequality sign, or we could follow the steps shown below

  • -2x < 10
  • 0 < 10+2x ... adding 2x to both sides
  • -10 < 2x ... subtracting 10 from both sides; this is one way to see why the sign flip happens
  • 2x > -10
  • x > -10/2 ..... dividing both sides by 2
  • x > -5
4 0
3 years ago
Solve for x.<br><br> x^3=1/27
Tatiana [17]
<em>1/3 is answer. Hope it helps

</em>
7 0
3 years ago
Find the imaginary solutions to the following quadratic function:
Temka [501]

Answer:

the solutions are these

Step-by-step explanation:

\frac{3}{14}  +  \frac{ \sqrt{159} }{14} i \: and  \\ \: \frac{3}{14}   -  \frac{ \sqrt{159} }{14} i

8 0
3 years ago
Solve by completing the square
Sveta_85 [38]

\qquad\qquad\huge\underline{{\sf Answer}}☂

Let's solve ~

\qquad \sf  \dashrightarrow \:  {x}^{2} + 8x = 33

\qquad \sf  \dashrightarrow \:  {x}^{2} + 8x +16 = 33 + 16

\qquad \sf  \dashrightarrow \: (x + 4) {}^{2}  = 49

\qquad \sf  \dashrightarrow \: x + 4 =  \sqrt{49}

\qquad \sf  \dashrightarrow \: x + 4 =  \pm7

Hence, there are two solutions ~

  • 1. when x + 4 = 7

\qquad \sf  \dashrightarrow \: x + 4 = 7

\qquad \sf  \dashrightarrow \: x = 7 - 4

\qquad \sf  \dashrightarrow \: x = 3

  • 2. when x + 4 = -7

\qquad \sf  \dashrightarrow \: x + 4 =  - 7

\qquad \sf  \dashrightarrow \: x  =  - 7 - 4

\qquad \sf  \dashrightarrow \: x  =   - 11

I hope you understood ~

8 0
2 years ago
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