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3 years ago

Write the raito as a fraction simplest from 12 boys and 15 girls

Mathematics

1 answer:

kiruha [24]3 years ago

3 0

Step-by-step explanation: We can write a ratio using the word "to", using a colon, or using a fraction bar.

Here, since we want our ratio in simplest form,

I would use a fraction bar.

Now, the problem asks us to compare

the number of boys to the number of girls.

We know that there are 12 boys

and we know that there are 15 girls.

So our ratio is 12/15.

However, this can be reduced to 4/5.

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Yoghurts are packed in trays. Each tray holds 12 yoghurts.

iogann1982 [59]

460/12 = 33.3 so about 32 trays if the smallest and 33 as the answer but best would be 33

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1 year ago

Find the range.<br><br>3 -9 7 -1 5 -4 2

ikadub [295]

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3 years ago

What Is The Rate Of Change In This Function?

Marrrta [24]

Answer:The answer would be 35 miles per day.

Step-by-step explanation:

We know the x axis is in days and the y axis is the distance in miles. There are only three answers left. We can also cross out 50 miles per day since the rate of change is less then 50. The answer is 35 miles per day because if the rate of change were to be 25 in 4 days the distance would be 100 miles, while is you look at where the point is at it is closer to 150.

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3 years ago

What is the length of the arc if: 11. r=10 n=20 A15(pi)/ 7 B13(pi)/ 5 C16(pi)/ 2 D11(pi)/ 4 E 10(pi)/ 9 F 9(pi)/ 4 12. r=3 n=6 A

Vilka [71]

Step-by-step explanation:

The formula for arc length [for the angle in degrees] is:

$L = 2\pi r \left(\dfrac{n}{360}\right)$

here,

$n$ = degrees

$r$ = radius

using this we'll solve all the parts:

r = 10, n = 20:

$L = 2\pi r \left(\dfrac{n}{360}\right)$

$L = 2\pi (10) \left(\dfrac{20}{360}\right)$

from here, it is just simplification:

2 and 360 can be resolved: 360 divided by 2 = 180

$L = \pi (10) \left(\dfrac{20}{180}\right)$

10 and 180 can be resolved: 180 divided by 10 = 18

$L = \pi \left(\dfrac{20}{18}\right)$

finally, both 20 and 18 are multiples of 2 and can be resolved:

$L = \pi \left(\dfrac{10}{9}\right)$

$L = \dfrac{10\pi}{9}$ Option (E)

r=3, n=6:

$L = 2\pi r \left(\dfrac{n}{360}\right)$

$L = 2\pi (3) \left(\dfrac{6}{360}\right)$

$L = \dfrac{\pi}{10}$ Option (D)

r=4 n=7

$L = 2\pi r \left(\dfrac{n}{360}\right)$

$L = 2\pi (4) \left(\dfrac{7}{360}\right)$

$L = \dfrac{7\pi}{45}$ Option (C)

r=2 n=x

$L = 2\pi r \left(\dfrac{n}{360}\right)$

$L = 2\pi (2) \left(\dfrac{x}{360}\right)$

$L = \dfrac{x\pi}{90}$ Option (D)

r=y n=x

$L = 2\pi r \left(\dfrac{n}{360}\right)$

$L = 2\pi (y) \left(\dfrac{x}{360}\right)$

$L = \dfrac{xy\pi}{180}$ Option (E)

6 0

3 years ago

The Wall Street Journal reported that Walmart Stores Inc. is planning to lay off 2300 employees at its Sam's Club warehouse unit

Advocard [28]

Answer:

(a) The mean is 52 and the median is 55.

(b) The first quartile is 44 and the third quartile is 60.

(d) The variance is 100.143 and the standard deviation is 10.01.

(e) There are no outliers in the data set.

(f) Yes

Step-by-step explanation:

The data provided is:

S = {55, 56, 44, 43, 44, 56, 60, 62, 57, 45, 36, 38, 50, 69, 65}

(a)

Compute the mean of the data as follows:

$\bar x=\frac{1}{n}\sum x\\=\frac{1}{15}[55+ 56+ 44+ 43+ 44+ 56+ 60+ 62+ 57+ 45 +36 +38 +50 +69+ 65]\\=\frac{780}{15}\\=52$

Thus, the mean is 52.

The median for odd set of values is the computed using the formula:

$Median=(\frac{n+1}{2})^{th}\ obs.$

Arrange the data set in ascending order as follows:

36, 38, 43, 44, 44, 45, 50, 55, 56, 56, 57, 60, 62, 65, 69

There are 15 values in the set.

Compute the median value as follows:

$Median=(\frac{15+1}{2})^{th}\ obs.=(\frac{16}{2})^{th}\ obs.=8^{th}\ observation$

The 8th observation is, 55.

Thus, the median is 55.

(b)

The first quartile is the middle value of the upper-half of the data set.

The upper-half of the data set is:

36, 38, 43, 44, 44, 45, 50

The middle value of the data set is 44.

Thus, the first quartile is 44.

The third quartile is the middle value of the lower-half of the data set.

The upper-half of the data set is:

56, 56, 57, 60, 62, 65, 69

The middle value of the data set is 60.

Thus, the third quartile is 60.

(c)

The range of a data set is the difference between the maximum and minimum value.

Maximum = 69

Minimum = 36

Compute the value of Range as follows:

$Range =Maximum-Minimum\\=69-36\\=33$

Thus, the value of range is 33.

The inter-quartile range is the difference between the first and third quartile value.

Compute the value of IQR as follows:

$IQR=Q_{3}-Q_{1}\\=60-44\\=16$

Thus, the inter-quartile range is 16.

(d)

Compute the variance of the data set as follows:

$s^{2}=\frac{1}{n-1}\sum (x_{i}-\bar x)^{2}\\=\frac{1}{15-1}[(55-52)^{2}+(56-52)^{2}+...+(65-52)^{2}]\\=100.143$

Thus, the variance is 100.143.

Compute the value of standard deviation as follows:

$s=\sqrt{s^{2}}=\sqrt{100.143}=10.01$

Thus, the standard deviation is 10.01.

(e)

An outlier is a data value that is different from the remaining values.

An outlier is a value that lies below 1.5 IQR of the first quartile or above 1.5 IQR of the third quartile.

Compute the value of Q₁ - 1.5 IQR as follows:

$Q_{1}-1.5QR=44-1.5\times 16=20$

Compute the value of Q₃ + 1.5 IQR as follows:

$Q_{3}+1.5QR=60-1.5\times 16=80$

The minimum value is 36 and the maximum is 69.

None of the values is less than 20 or more than 80.

Thus, there are no outliers in the data set.

(f)

Yes, the data provided indicates that the Walmart is meeting its goal for reducing the number of hourly employees

6 0

3 years ago

Write the raito as a fraction simplest from 12 boys and 15 girls​

Write the raito as a fraction simplest from 12 boys and 15 girls