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Alenkinab [10]
2 years ago
12

What is the area of square EFGH?

Mathematics
1 answer:
rodikova [14]2 years ago
8 0
The area of the square EFGH is 98.8 in^2
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Helppp me please IREADY​
Morgarella [4.7K]

Hello there! The answer is the first option, 31/55.

To solve this, we don't even need to do any math. Note that fractions with the same numerator and denominator will be equal to 1.

Knowing this and looking at our second and fourth options, 55/55 x 111 and 31/31 x 111, these problems are the same as 1 x 111, which results in 111, which is not less than, leaving us with the third and first options.

The third option is 55/31, meaning we have more than a whole, so we are multiplying by a number greater than 1, making our answer over 111 and this option not correct.

This leaves the first option as your answer!

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3 years ago
Express each ratio as a fraction in lowest terms.
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2) 11/77 simplified into 1/7
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Which angles are vertical to
ArbitrLikvidat [17]
GAH is vertical to FAE
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3 years ago
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Based on the diagram, what is sinA
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\sin(A)  =  \frac{BC}{AB}  =  \frac{a}{c}

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Answer ASAP In the given diagram, ∠4 = 45°, ∠5 = 135° and ∠10 = ∠11 Part A: Solve for the values of the remaining angles. Show a
MaRussiya [10]

Answer:

A) ∠9 = ∠10 = ∠11 = ∠12  = 90°

∠2 = ∠3 = ∠5 = ∠8 = 135°

∠1 = ∠4 = ∠6 = ∠7 = 45°

B) 1. ∠4 and ∠1 -> vertical angles

2. ∠7 and ∠5 -> supplementary

3. ∠9 and ∠10 -> supplementary

Step-by-step explanation:

<u>Data</u>

  • ∠4 = 45°
  • ∠5 = 135°
  • ∠10 = ∠11

The following are vertical angles, so they are congruent:

∠1 ≅ ∠4

∠3 ≅ ∠2

∠11 ≅ ∠9

∠10 ≅ ∠12

∠7 ≅ ∠6

∠5 ≅ ∠8

From here and data, it is deduced that

∠11 ≅ ∠9 ≅ ∠10 ≅ ∠12

From the picture, the addition of them is equal to 360°, then:

∠11 + ∠9 + ∠10 + ∠12 = 360°

4*∠11 = 360°

∠11 = 360°/4

∠11 = 90° = ∠10 = ∠9 = ∠12

∠2 and ∠4 are supplementary, then:

∠2 + ∠4 = 180°

∠2 = 180° - 45°

∠2 = 135°

∠7 and ∠5 are supplementary, then:

∠7 + ∠5 = 180°

∠7 = 180° - 135°

∠7 = 45°

6 0
3 years ago
Read 2 more answers
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