Find two consecutive integers whose product is 6 less than the square of the smaller number
1 answer:
Answer:
Hi there!
Your answer is:
The smaller integer is -6
The larger integer is -5
Step-by-step explanation:
Two consecutive integers:
x, x+1
Product= multiply
(x) × (x+1) = x^2 - 6
x^2 + x= x^2 -6
-x^2
x= -6
Plug back in
First integer (smaller):
-6
Second integer (larger):
-6+1
-5
<u>Check</u><u> </u><u>your </u><u>work</u><u>!</u>
(-6) × (-6+1)
(-6)× (-5)
30 = (-6)^2 -6
30 = 36-6
30= 30 ✓✓✓✓
That's how we determine that <em>this </em><em>is</em><em> </em><em>the</em><em> </em><em>corr</em><em>ect</em><em> </em><em>answe</em><em>r</em>
Hopefully this helps
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