Find two consecutive integers whose product is 6 less than the square of the smaller number
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Answer:
110
Step-by-step explanation:
Let's define . So when we divide it by 'x+1', we can use Bezout's Theorem which states: that any polynomial(P(X)) divided by another binomial in the form 'x - a', then the remainder will be P(a).
We can use this fact to determine the remainder, because we divided our P(X) by x + 1 which is the same as x - (-1). So we plug in P(-1).
P(-1) = (-1)^11 + 101 = -1 + 101 = 110