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salantis [7]
4 years ago
6

A scientist studying insect starts with a population of 10. The population triples every hour. How many insects with be there in

20 minutes.
Mathematics
2 answers:
atroni [7]4 years ago
8 0
The question is asking you to understand that a population which is raised by a common ratio over a certain time period follows an exponential pattern. See:

After 1 hour, the population is 3*10
After 2 hours, the population is 3*3*10
After 3 hours, the population is 3*3*3*10
.....

This can be generalised as a function of t, the time in hours:

f(t) = (3^t) * 10

Since the function determines the population at a given time, it is more prudent to replace f(t) with P, the population after time t:

P = (3^t) * 10

Since 20 minutes is equal to (1/3) hours, t can be substituted for (1/3) in order to calculate the population size after 20 minutes:

P = (3^(1/3)) * 10 = 14.4224957031 <span>≈ 14

Therefore the population after 20 minutes is 14.</span>
Kobotan [32]4 years ago
3 0

Answer:

14

Step-by-step explanation:

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Jill’s room is 12 feet long and 10 feet wide. she made a scale drawing of the room with a scale of 0.5 inches = 2 feet. what is
umka21 [38]
12/2=6.
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4 years ago
Guys I need help pleaSe !!!
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Answer:

The equations that represent an exponential decay are;

A; [y = (0.1)ˣ]

B; [y = 2·(0.3)ˣ]

Step-by-step explanation:

An exponential decay is given by the following formula;

y = a·bˣ

Where;

b < 1

For option A, we have; [y = (0.1)ˣ]

Here; a = 1, b = 0.1 < 1, therefore, the function represents an exponential decay

For option B, we have; [y = 2·(0.3)ˣ]

Here; a = 2, b = 0.3 < 1, therefore, the function represents an exponential decay

For option C, we have; \left[y = \left(\dfrac{4}{3} \right)^x\right]

Here; a = 1, b = \dfrac{4}{3} \right) > 1, therefore, the function does not represent an exponential decay

For option D, we have; \left[y = \left(\dfrac{7}{5} \right)^x\right]

Here; a = 1, b = \dfrac{7}{5} \right) > 1, therefore, the function does not represent an exponential decay

6 0
3 years ago
Find the sum. 13(9−6m)+14(12m−8)
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To do this problem, we must first distribute the 13 and 14 into the parenthesis.

<span>13(9−6m)+14(12m−8)

117 - 78m + 168m - 112

To combine like terms, we can add/subtract terms that have an "m" together and then we can add/subtract terms that do not have "m" together.

117 - 112 = 5
and 
168m - 78m = 90m

So our final sum is 5 + 90m</span>
7 0
3 years ago
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