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Darina [25.2K]
3 years ago
6

Beth won 53 pieces of gum playing basketball at her school's game night. Later, she gave two to each of her friends. She only ha

s 3 remaining. How many friends does she have?
Mathematics
1 answer:
HACTEHA [7]3 years ago
5 0
She has 25 friends, if she only has 3 pieces that means she game away 50 pieces of gum, 50/2 is 25.
You might be interested in
An electrical firm manufactures light bulbs that have a length of life that is approximately normally distributed, with mean equ
kompoz [17]

Answer:

0.62% probability that a random sample of 16 bulbs will have an average life of less than 775 hours.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}

Normal probability distribution.

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 800, \sigma = 40, n = 16, s = \frac{40}{\sqrt{16}} = 10

Find the probability that a random sample of 16 bulbs will have an average life of less than 775 hours.

This probability is the pvalue of Z when X = 775. So

Z = \frac{X - \mu}{s}

Z = \frac{775 - 800}{10}

Z = -2.5

Z = -2.5 has a pvalue of 0.0062. So there is a 0.62% probability that a random sample of 16 bulbs will have an average life of less than 775 hours.

5 0
3 years ago
AC=CE and D is the midpoint of CE. If CE = 10x+18 DE = 7x-1 and BC = 9x-3 find AB
Mazyrski [523]

We know the CE = 10x + 18 and DE = 7x - 1 and D is the midpoint of CE

⇒ CE = 2 * DE

⇒ 10x + 18 = 2 * (7x - 1)

⇒ 10x + 18 = 14x - 2

⇒ -4x = -20

⇒ x = 5

Now we also know that BC = 9x - 3 and AC = CE = 10x + 18

⇒ AB = AC - BC

⇒ AB = 10x + 18 - (9x - 3)

⇒ AB = x + 21

Substituting the value of x,

⇒ AB = 5 + 21

⇒ AB = 26

Hence, the value of AB is 26 units.


8 0
3 years ago
Algebra hcf<br>10xyz and 15y²z²​
boyakko [2]

Answer:

5yz

Step-by-step explanation:

1st expression=10xyz

=<u>5</u>*2*x*<u>y</u>*<u>z</u>

2nd expression=15(y)2 (z)2

=<u>5</u>*3*<u>y</u>*y*z*<u>z</u>

therefore H.C.F=5yz

underlines are taking common.

3 0
2 years ago
Explain how you would factor 9x^2 – 49 show your work and use complete sentences. what is this special type of factoring called?
tatuchka [14]
9x² - 49

(3x)² - (7)²

= (3x + 7)(3x - 7)

This type of factoring is called Difference of Two Squares

where x² - y² = (x + y)(x - y)
3 0
3 years ago
3/5 + -1/5 ÷ 1/4 ÷ -1/3​
aleksandr82 [10.1K]

Answer:3

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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