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The equation modeling the height of the ball at time,t is given by h=-16t²+48t+6
<span>a. In how many seconds does the ball reach its maximum height?
Time taken for the ball to reach the maximum height will be given by:
h'(t)=-32t+48=0
finding the value of t we get:
32t=48
t=48/32
t=1.5 seconds
Thus the time taken for the ball to reach the maximum time is 1.5 seconds
b]</span><span> What is the ball’s maximum height?
The maximum height will be:
h(1.5)=-16(1.5)</span>²+48(1.5)+6
h(1.5)=42 fee
Answer:
x=5
Step-by-step explanation:
hey there
the angles given are corresponding angles meaning that they are congruent
so we set up an equation
23x-5=21x+5
step 1 subtract each side by 5
5-5 cancels out
-5-5=-10
now we have
23x-10=21x
step 2 subtract each side by 23x
21x-23x=-2x
now we have
-2x=-10
step 3 divide each side by 2
-10/-2=5
so we can conclude that
x=5
Answer:
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