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Rufina [12.5K]
3 years ago
14

The first four terms of a sequence are shown below. 6, 2, -2, -6 Which of the following functions best defines this sequence?

Mathematics
1 answer:
klasskru [66]3 years ago
3 0
Where are the functions?
your question is incomplete?
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for freinds share 32 tokens at the arcade .if they share them equally ,what fraction of tokens will each person get?            
Anvisha [2.4K]
32/4=8

----------

Each person will get 8 tokens. 8 tokens turns out to be a quarter of the tokens that are available.
6 0
3 years ago
Read 2 more answers
You have an SRS of size 8 and calculate the one-sample t statistic. What is the critical value t∗ such that (a) t has probabilit
Rudik [331]

Answer:

a) "=T.INV(1-0.02,7)"

And we got t_{crit}= 2.518

b) "=T.INV(0.85,7)"

And we got t_{crit}= 1.119

Step-by-step explanation:

For this case we have a sample size of n=8, so we can find the degrees of freedom like this:

df = n-1 = 8-1 =7

Part a

For this case we need a value who accumulates 0.02 of the area in the right of the t distribution with 7 degrees of freedom so we can use the following excel code:

"=T.INV(1-0.02,7)"

And we got t_{crit}= 2.518

Part b

For this case we need a value who accumulates 0.85 of the area in the left of the t distribution with 7 degrees of freedom so we can use the following excel code:

"=T.INV(0.85,7)"

And we got t_{crit}= 1.119

7 0
3 years ago
(2x²ⁿ₊3x²ⁿ⁻¹)(x¹⁻²ⁿ₋3x²⁻²ⁿ)
Tcecarenko [31]

Answer:

2x²ⁿ₊3x²ⁿ⁻¹)(x¹⁻²ⁿ₋3x²⁻²ⁿ)

Step-by-step explanation:

2x²ⁿ₊3x²ⁿ⁻¹)(x¹⁻²ⁿ₋3x²⁻²ⁿ)

8 0
2 years ago
14.976 divided by 6 with remainder
PIT_PIT [208]

Answer:

0

Step-by-step explanation:

it's divided evenly with no remainder

4 0
3 years ago
Read 2 more answers
10. The expression 3(2+x) is a product of the factors 3 and
Trava [24]

Answer:

Step-by-step explanation:

10. 2 ( 3 times 2 = 6, The three and two are both factors)

11. 3(2+x)= 6+3x If you do distributive property you have to multiply times 3 of everything in the parentheses

12. I don't see the image sorry.

4 0
3 years ago
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