Question

What is the output from the following code? MapInterface m; m = new ArrayListMap(); m.put('D', "dog"); m.put('P', "pig"); m.put('C', "cat"); m.put('P', "pet"); System.out.println(m.get('D')); System.out.println(m.get('E')); System.out.println(m.get('P'));

Answer 1

Answer: dog

null

pet

Explanation:

taking into condiserations the various animals and their tag given to them;

OUTPUT :

dog

null

pet

PROOF:

Where the Initially map : {}

after map.put('D', "dog"), map : {'D':"dog"}

after map.put('P', "pig"), map : {'D':"dog", 'P':"pig"}

after map.put('C', "cat"), map : {'D':"dog", 'P':"pig", 'C':"cat"}

after map.put('P', "pet"), map : {'D':"dog", 'P':"pet", 'C':"cat"}, what this does is replace the  value of P with "pet"

map.get('D') prints dog.

map.get('E') prints null, key is not present

map.get('P') prints pet

cheers I hope this helped !!