I need the help with both questions & need to show work. Thank u

Mathematics

1 answer:

Ira Lisetskai [31]3 years ago

8 0

#1. The answer is B, just put the points on the graphic and you will see.

#2. The answer is A, the equation explained everything.

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Twenty girls (ages 9-10) competed in the 50-meter freestyle event at a local swim meet. The mean time was 43.70 seconds with a

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Answer:

Right or positively skewed

Step-by-step explanation:

From the median and the interquartile range we can find the first and third quartile values Q3=40.15+(4.98/2)=42.64 and Q1=37.66.

Now we have enough evidence to conclude that is Right or positively skewed

1. The mean is above the median

2. The mean is 43.70, which is above the third quartile (42.64), meaning that after the mean there's less than 30% of the data.

The evidence suggests that most of the data is concentrated at the bottom of the distribution making it right or positively skewed.

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3 years ago

Is this the right answer

nevsk [136]

You would have to change it into an improper fraction which you would just subtract 14 from the numerator

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3 years ago

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How can Sue use the converse of the Pythagorean Theorem to find out if a triangle with side lengths 28, 53, and 45 is a right tr

timama [110]

Answer:

Step-by-step explanation:

28²+45²=53²

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3 years ago

A teacher was interested in knowing the amount of physical activity that his students were engaged in daily. He randomly sampled

klasskru [66]

Answer:

The standard error of the mean is 4.5.

Step-by-step explanation:

As we don't know the standard deviation of the population, we can estimate the standard error of the mean from the standard deviation of the sample as:

$\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}$

The sample is [30mins, 40 mins, 60 mins, 80 mins, 20 mins, 85 mins]. The size of the sample is n=6.

The mean of the sample is:

$\bar{x}=\frac{1}n} \sum x_i =\frac{30+40+60+80+20+85}{6}=52.5$

The standard deviation of the sample is calculated as:

$s=\sqrt{\frac{1}{n-1}\sum (x_i-\bar x)^2} \\\\ s=\sqrt{\frac{1}{5}\cdot ((30-52.5)^2+(40-52.5)^2+(60-52.5)^2+(80-52.5)^2+(20-52.5)^2+(85-52.5)^2}\\\\s=\sqrt{\frac{1}{5} *3587.5}=\sqrt{717.5}=26.8$