A rhombus is quadrilateral where all 4 sides are of equal length. Thus
5x + 2 = 2x + 12
3x = 10
x = 10/3
substituting x into either expression, yields
56/3
therefore side AB = 56/3
Answer:
That is the solutions are:
,
Step-by-step explanation:
The period of
or
is
.
Let's look at the first rotation to see when
happens.
This happens at
and also at
. (Notice I just looked at the x-coordinates because that is what cosine is. Sine is the y-coordinate.)
Now to find the rest of the solutions we can just make full rotations either way to get back to those points .
That is the solutions are:


The other number is 5 less than 3 times the other so the other number will be
3x-5
We are given that they add up to 31, so we can write
x+(3x-5) = 31
4x - 5 =31