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klemol [59]
3 years ago
13

If BOTH equations are in slope-intercept form then the--------------? method would be best, but the------------? method would al

so be effective since both y's are already by itself.
If ONE of the equations is solved for x or y and the other equation is not, then the----------? method is best.

If BOTH equations are lined up in standard form & the coefficients of x or y are opposites then the BEST method is definitely the-----------? method.

If BOTH equations are lined up in standard form the elimination method would be best. But if the coefficient of x or y is 1, then the-------------? method is also effective.




PLZ HELP MEEE WITH THIS
Mathematics
1 answer:
nadezda [96]3 years ago
5 0

Answer:

Step-by-step explanation:

If BOTH equations are in slope-intercept form then the-graphing-? method would be best, but the-substitution-? method would also be effective since both y's are already by itself.

If ONE of the equations is solved for x or y and the other equation is not, then the-substitution-? method is best.

If BOTH equations are lined up in standard form & the coefficients of x or y are opposites then the BEST method is definitely the-elimination--? method.

If BOTH equations are lined up in standard form the elimination method would be best. But if the coefficient of x or y is 1, then the-substitution--? method is also effective.

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Question on picture. Please help
Elden [556K]
A rhombus is quadrilateral where all 4 sides are of equal length. Thus


5x + 2 = 2x + 12

3x = 10

x = 10/3

substituting x into either expression, yields

56/3

therefore side AB = 56/3


3 0
3 years ago
Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to two decimal places
Ghella [55]

Answer:

That is the solutions are:

\frac{\pi}{3}+2\pi \cdot k,\frac{5\pi}{3}+2\pi \cdot k

Step-by-step explanation:

The period of \cos(x) or \sin(x) is 2\pi.

Let's look at the first rotation to see when \cos(\theta)=\frac{1}{2} happens.

This happens at \frac{\pi}{3} and also at \frac{5\pi}{3}. (Notice I just looked at the x-coordinates because that is what cosine is. Sine is the y-coordinate.)

Now to find the rest of the solutions we can just make full rotations either way to get back to those points .

That is the solutions are:

\frac{\pi}{3}+2\pi \cdot k

\frac{5\pi}{3}+2\pi \cdot k

7 0
4 years ago
<img src="https://tex.z-dn.net/?f=c%3D%202%5Cpi%20r" id="TexFormula1" title="c= 2\pi r" alt="c= 2\pi r" align="absmiddle" class=
astraxan [27]
Divide both sides by 2pi
\frac{c}{2\pi}=r
6 0
3 years ago
The number of sails you could make for $10,000 if the sail material costs $30 per square yard
dexar [7]
My teacher said 45$
4 0
3 years ago
HELP NOW PLEASE
Nonamiya [84]

The other number is 5 less than 3 times the other so the other number will be

3x-5

We are given that they add up to 31, so we can write

x+(3x-5) = 31

4x - 5 =31 

3 0
3 years ago
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