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TEA [102]
3 years ago
15

How do u write 668 to 900 using ones, tens and hundreds

Mathematics
2 answers:
Nesterboy [21]3 years ago
8 0
600+60+8 and 900+0+0
Gwar [14]3 years ago
5 0
600+ 60 + 8 and 900 + 0 +0, I hope that's what you wanted
You might be interested in
Find the product.<br> (z + 3i)(z − 3i)
Doss [256]

Answer:

First, we use distributive property:

(z+3i)(z-3i)=z^2-3zi+3zi-9i^2

Now, remember that i^2=-1, then

z^2-3zi+3zi-9i^2=z^2-9(-1)=z^2+9

Then,

(z+3i)(z-3i)=z^2+9

8 0
3 years ago
A flower show has an inventory of 60 tulips and 100 roses. Which equation is correct?
Zinaida [17]

Answer:

The correct equitation is 60=\frac{3}{5}\times10060=

5

3

×100 OR 100=\frac{5}{3}\times60100=

3

5

×60

Step-by-step explanation:

To determine:

A flower show has an inventory of 60 tulips and 100 roses?

Information Fetching and Solution Steps:

A flower show has an inventory of

60 tulips

100 roses

So,

60=\frac{3}{5}\times10060=

5

3

×100

or

100=\frac{5}{3}\times60100=

3

5

×60

Other options can not be true as they do not satisfy the equation. For example,

60 = 3\times 10060=3×100 can not be true as the L.H.S ≠ R.H.S

Therefore, the correct equitation is 60=\frac{3}{5}\times10060=

5

3

×100 OR 100=\frac{5}{3}\times60100=

3

5

×60

5 0
3 years ago
The image of the point (7,-4) under a translation is (12,-5). Find the coordinates
Afina-wow [57]
The translation is right 5, down 1, AKA (x+5, y-1). The original coordinate of the point given is (-8,-3). Use the same translation so ((-8 + 5), (-3 - 1)) = (-3,-4)
3 0
3 years ago
Which value, when placed in the box, would result in a system of equations with infinitly many solutions? Y=2x - 5 2y-4x=
Nezavi [6.7K]

Given:

The system of equations is

y=2x-5

2y-4x=?

To find:

The missing value for which the given system of equations have infinitely many solutions.

Solution:

Let the missing value be k.

We have,

y=2x-5

2y-4x=k

Taking all the terms on the left side, the given equations can be rewritten as

-2x+y+5=0

-4x+2y-k=0

The system of equations a_1x+b_1y+c_1=0 and a_2x+b_2y+c_2=0 have infinitely many solutions if

\dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}=\dfrac{c_1}{c_2}

We have,

a_1=-2,b_1=1,c_1=5

a_2=-4,b_2=2,c_2=-k

Now,

\dfrac{-2}{-4}=\dfrac{1}{2}=\dfrac{5}{-k}

\dfrac{1}{2}=\dfrac{1}{2}=\dfrac{5}{-k}

\dfrac{1}{2}=\dfrac{5}{-k}

On cross multiplication, we get

-k=10

k=-10

Therefore, the missing value is -10.

6 0
3 years ago
The fee to check luggage with a
Vlad [161]

Answer:

$10.71

Step-by-step explanation:

divide 7.14 by 42  to get the price per pound, then multiply that by 63.

8 0
3 years ago
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