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mr Goodwill [35]

3 years ago

15

Math is still my weak suit

1 answer:

Mama L [17]3 years ago

6 0

The Answer is 704 m2

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Wendy won 16% of the games she played. If she won 40 games, how many did she play?

Liula [17]

Let x = total games played

16% = 0.16

0.16x = 40. Divide each number by 0.16.

x = 250

Wendy played 250 games

7 0

3 years ago

a meal at a restaurant cost $49.28. If the customers leave $8.23 for to determine the tip rate to the nearest whole percent. Wha

Monica [59]

Now, if the customers left 8.23 extra, based on a percentage of the cost of the meal, namely, the 8.23 is a percent of 49.28, then

if we take 49.28 to be the 100%, how much of a percentage is 8.23?

$\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
49.28&100\\
8.23&t
\end{array}\implies \cfrac{49.28}{8.23}=\cfrac{100}{t}\implies t=\cfrac{8.23\cdot 100}{49.28}$

8 0

3 years ago

Please help me don't understand :(

qaws [65]

Answer:

I think it's the last one. Sorry if I'm wrong

8 0

3 years ago

23. If 25% of a number is 75. find the number.<br>A. 700 B. 600 C. 500 D, 400 E. 300

nadya68 [22]

Answer:

<em><u>2</u></em><em><u>3</u></em><em><u>.</u></em><em><u>E</u></em>

Step-by-step explanation:

<em><u>please click the heart and rate excellent and brainleist to </u></em><em><u>☻</u></em><em><u>❤</u></em><em><u>☺️</u></em><em><u>☺️</u></em><em><u>❤</u></em><em><u>☻</u></em>

4 0

3 years ago

Read 2 more answers

9. A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

SSSSS [86.1K]

Answer:

Part 4) $r=84\ units$

Part 9) $sin(\theta)=-\frac{\sqrt{5}}{3}$

Part 10) $sin(\theta)=-\frac{9\sqrt{202}}{202}$

Step-by-step explanation:

Part 4) A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

we know that

The circumference of a circle subtends a central angle of 360 degrees

The circumference is equal to

$C=2\pi r$

using proportion

$\frac{2\pi r}{360^o}=\frac{56\pi}{120^o}$

simplify

$\frac{r}{180^o}=\frac{56}{120^o}$

solve for r

$r=\frac{56}{120^o}(180^o)$

$r=84\ units$

Part 9) Given cos(∅)=-2/3 and ∅ lies in Quadrant III. Find the exact value of sin(∅) in simplified form

Remember the trigonometric identity

$cos^2(\theta)+sin^2(\theta)=1$

we have

$cos(\theta)=-\frac{2}{3}$

substitute the given value

$(-\frac{2}{3})^2+sin^2(\theta)=1$

$\frac{4}{9}+sin^2(\theta)=1$

$sin^2(\theta)=1-\frac{4}{9}$

$sin^2(\theta)=\frac{5}{9}$

square root both sides

$sin(\theta)=\pm\frac{\sqrt{5}}{3}$

we know that

If ∅ lies in Quadrant III

then

The value of sin(∅) is negative

$sin(\theta)=-\frac{\sqrt{5}}{3}$

Part 10) The terminal side of ∅ passes through the point (11,-9). What is the exact value of sin(∅) in simplified form?

see the attached figure to better understand the problem

In the right triangle ABC of the figure

$sin(\theta)=\frac{BC}{AC}$

Find the length side AC applying the Pythagorean Theorem

$AC^2=AB^2+BC^2$

substitute the given values

$AC^2=11^2+9^2$

$AC^2=202$

$AC=\sqrt{202}\ units$

so

$sin(\theta)=\frac{9}{\sqrt{202}}$

simplify

$sin(\theta)=\frac{9\sqrt{202}}{202}$

Remember that

The point (11,-9) lies in Quadrant IV

then

The value of sin(∅) is negative

therefore

$sin(\theta)=-\frac{9\sqrt{202}}{202}$

5 0

3 years ago