It would be n - 5
It’s saying 5 LESS than a number so 5 would be subtracted
Hope this helps!
4x^2(2x+1)-9(2x+1)=0
(4x^2-9)(2x+1)=0
(2x-3)(2x+3)(2x+1)=0
The prime factorization of 64 is 8.
Answer:
215.16
Step-by-step explanation:
1/3(48.9)(13.2)=215.16
Solve the first for y
y=13x-90 and the second is y=x^2-x-42
When there is/are solutions y=y so we can say:
x^2-x-42=13x-90 subtract 13x from both sides
x^2-14x-42=-90 add 90 to both sides
x^2-14x+48=0 expand so that it is easy to factor...
x^2-6x-8x+48=0 now factor 1st and 2nd pair of terms
x(x-6)-8(x-6)=0
(x-8)(x-6)=0
So there are two solutions, when x=6 and 8.
Using either original equation we can find the corresponding values for y. I'll use y=13x-90 because it is easier...
y(6)=-12, y(8)=14 so the two solutions are the points:
(6,-12) and (8,14)
