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AlexFokin [52]
3 years ago
14

How is copper measured and monitored in the environment

Biology
1 answer:
vovangra [49]3 years ago
3 0

Most copper compounds tend to settle down near the water sediments or near the soil particles and can be monitored from there.

<u>Explanation:</u>

Copper can be discharged into the earth by both natural sources and human exercises. Copper is regularly found close to mines, modern settings, landfills and waste removals. Most copper mixes will settle and will undoubtedly either water silt or soil particles.

Copper doesn't separate in the earth and due to that it can gather in plants and creatures when it is found in soils. At the point when the dirt of farmland are dirtied with copper, animals will assimilate fixations that are harming to their well being.

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A fish maintains its depth in fresh water by adjusting the air content of porous bone or air sacs to make its average density th
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Answer:

0.153

Explanation:

We know the up-thrust on the fish, U = weight of water displaced = weight of fish + weight of air in air sacs.

So ρVg = ρ'V'g + ρ'V"g where ρ = density of water = 1 g/cm³, V = volume of water displaced, g = acceleration due to gravity, ρ'= density of fish = 1.18 g/cm³, V' = initial volume of fish, ρ"= density of air = 0.0012 g/cm³ and V" = volume of expanded air sac.

ρVg = ρ'V'g + ρ"V"g

ρV = ρ'V'g + ρ"V"

Its new body volume = volume of water displaced, V = V' + V"

ρ(V' + V") = ρ'V' + ρ"V"

ρV' + ρV" = ρ'V' + ρ"V"

ρV' - ρ"V'  = ρ'V" - ρV"

(ρ - ρ")V'  = (ρ' - ρ)V"

V'/V" = (ρ - ρ")/(ρ' - ρ)

= (1 g/cm³ - 0.0012 g/cm³)/(1.18 g/cm³ - 1 g/cm³)

= (0.9988 g/cm³ ÷ 0.18 g/cm³)

V'/V" = 5.55

Since V = V' + V"

V' = V - V"

(V - V")/V" = 5.55

V/V" - V"/V" = 5.55

V/V" - 1 = 5.55

V/V" = 5.55 + 1

V/V" = 6.55

V"/V = 1/6.55

V"/V = 0.153

So, the fish must inflate its air sacs to 0.153 of its expanded body volume

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