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nignag [31]
2 years ago
8

Most network behavior analysis system sensors can be deployed in __________ mode only, using the same connection methods as netw

ork-based idpss.
Computers and Technology
1 answer:
soldier1979 [14.2K]2 years ago
7 0
Most network behavior analysis system sensors can be deployed in passive mode only, using the same connection methods as network based idpss. Idps works as a network or host based systems. Most Nba sensors can be deployed in passive mode only too. The Nba examines the network traffic.
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An online survey is an effective way for an administrative professional to gather information. True False
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Answer:

True is the correct answer for the above question.

Explanation:

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Which of the following items is not considered a personal risk factor for ergonomic hazards? A. Body size B. Medical condition C
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The theory of continental drift is supported by all of the following EXCEPT
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Program to count how many even and odd number are in the range from M to N using C++ programming language
NemiM [27]

Answer:

#include<stdio.h>

#include <iostream>

using namespace std;

 

int main(){

   int number, min, max;

   cout << "Enter the minimum range: ";

   cin >> min;

  cout << "Enter the maximum range: ";

   cin >> max;

   cout << "Odd numbers in given range are: ";

   for(number = min; number <= max; number++)

        if(number % 2 !=0)

            cout << number<< " ";

   cout<< "Even numbers in given range are: ";

   for(number = min; number <= max; number++)

        if(number % 2 ==0)

            cout << number << " ";

 

   return 0;

}

Explanation:

First of all, we take declare two variables. one as the lowest number of the range and the other as the upper limit of the range (in this case: <em>min</em> and <em>max</em>). We declare another variable (<em>number</em>) and store in it the lowest number of the range (<em>min</em>). To check whether the number currently stored as the value of the variable (<em>number</em>) is even, we take in account the remainder of that number divided by 2. If the remainder does not equals 0, we print that number as odd. We again check the remainder by dividing the number by 2. If the remainder does equals 0, we print that number as even.

8 0
2 years ago
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