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SSSSS [86.1K]
3 years ago
6

Enhancement of job satisfaction and productivity are key characteristics of which theoretical perspective of work design? ​

Computers and Technology
1 answer:
Pavlova-9 [17]3 years ago
3 0

Answer: Socio-technical systems

Explanation:

Sociotechnical systems refers to an approach to organizational work design whereby the interaction between people and technology in the workplace is recognized.

It should be noted that the welfare of the worker is emphasized in socio technical systems is emphasized in the form of motivation and job enrichment.

You might be interested in
(The Location class) Design a class named Location for locating a maximal value and its location in a two-dimensional array. The
-Dominant- [34]

Answer:

Here is the Location class:

public class Location {   //class name

   public int row;  // public data field to hold the value of no. of rows

   public int column;  // public data field to hold the value of no. of columns

   public double maxValue;   //public data field to hold the maximum value

   public Location(int row, int column, double maxValue) { //parameterized constructor of Location class

//this keyword is used to refer to a current instance variable and used to avoid naming conflicts between attributes and parameters with the same name

       this.row = row;  

       this.column = column;  

       this.maxValue = maxValue;     }  

   public static Location locateLargest(double[][] a) {   //method that takes a 2 dimensional array a as argument and returns the location of the largest element

       int row = 0;  //initializes row to 0

       int column = 0;  //initializes column to 0

       double maxValue = a[row][column];   //stores largest element

       for (int i = 0; i < a.length; i++) {  //iterates through rows of a[] array

           for (int j = 0; j < a[i].length; j++) {  //iterates through columns of array

               if (maxValue < a[i][j]) {  //if the maxValue is less than the element of 2 dimensional array at ith row and jth column

                   maxValue = a[i][j];  //then set that element to maxValue

                   row = i;  // i is set to traverse through rows

                   column = j;   }             }         }  // i is set to move through columns

       return new Location(row,column,maxValue);     }  } //calls constructor of class by passing row, column and maxValue as argument

Explanation:

Here is the Main class with a main() function to  test program  

import java.util.Scanner;   //to accept input from user

public class Main {   //class name

   public static void main(String[] args) {   //start of main function

       Scanner scan = new Scanner(System.in);  //creates Scanner class object to scan the input from user

 System.out.print("Enter the number of rows and columns in the array: ");  //prompt for user

       int row = scan.nextInt();  // reads value of row from user

       int column = scan.nextInt();  //reads input value of column

       double[][] array = new double[row][column];   //declares a 2 dimensional array named array

       System.out.println("Enter the array:");  //prompts to enter array elements

       for (int i = 0; i < array.length; i++) {  //iterates through the rows of array until the size of array is reaced

           for (int j = 0; j < array[i].length; j++) {  //iterates through the columns of array

               array[i][j] = scan.nextDouble();    }    }   //reads each element at i-th row and j-th column

       Location location = Location.locateLargest(array);  //calls locateLargest method by passing array to it in order to locate the largest element in the array

System.out.println("The largest element in a two-dimensional array is: " + location.maxValue);  //displays the largest element of array

       System.out.println("The location of the largest element is at (" + location.row + ", " + location.column + ")");       }    } //displays the location of the largest element in the two dimensional array

Suppose the user enters 2 rows and 2 columns. The elements are:

1         5.5

4.5      3

The program works as follows:

for (int i = 0; i < array.length; i++) this outer loop iterates through rows

i = 0

inner loop for (int j = 0; j < array[i].length; j++) iterates through columns

array[i][j] = scan.nextDouble(); reads the element at position i-th row and j-th column. This becomes:

array[0][0] = scan.nextDouble();

so element at 0th row and 0th column is 1

Location location = Location.locateLargest(array); now this calls the method which works as follows:

double maxValue = a[row][column]; this becomes:

double maxValue = a[0][0];

so maxValue = 1

for (int i = 0; i < a.length; i++) this loop in method iterates through rows and  for (int j = 0; j < a[i].length; j++) this iterates through columns of array

if (maxValue < a[i][j]) this becomes:

if (maxValue < a[0][0])

As we know that maxValue = 1 so this if condition is true.

                   maxValue = a[i][j];  this becomes:

             maxValue = a[0][0];  

maxValue = 1

Now set row = 0 and column = 0

Now the inner loop value of j is incremented to 1. So j = 1

At next iteration array[0][1] is checked. The element at this position is 5.5

if (maxValue < a[i][j]) is true because 1<5.5 so now value of maxValue becomes:

maxValue = 5.5

and

i = 0  j = 1

This way at each iteration of inner loop the columns are traversed and at each iteration of outer loop rows are traversed.

At next iteration element at array[1][0] is checked which is 4.5. This is not greater than maxValue so maxValue remains 5.5

At next iteration element at array[1][1] is checked which is 3. This is not greater than maxValue so maxValue remains 5.5 .

After both the loops end the statement:

return new Location(row,column,maxValue);

returns row , column and maxValue

where row = 0  column = 1 and maxValue = 5.5

So the output is:

The largest element in a two-dimensional array is: 5.5

The location of the largest element is at (0,1)

3 0
4 years ago
A poem for coduction
Nataly_w [17]
I don't know if you want a poem about conduction but if so here ya go

no matter how the heat
different temperatures meet
hot to cold how it's done
4 0
4 years ago
Read 2 more answers
Evaluate the expression. Be sure to list a value of appropriate type (e.g., 7.0 rather than 7 for a double, Strings in quotes).
Mashutka [201]
<h2>Answer:</h2>

14.0

<h2>Explanation:</h2>

Using the level of precedence in Java,

From left to right;

(i) the first division operation will be done.

(ii)followed by the second division operation.

(iii)followed by the first multiplication operation.

(iv)followed by the third division operation.

(v)followed by the second multiplication operation.

(vi) followed by the first addition operation.

(vii)lastly followed by the second addition operation.

=================================================

Taking the steps above one after the other;

<em>(i) the first division operation will be done (i.e 19 / 2)</em>

=> Integer division in Java gives an integer result. Therefore, 19 / 2 = 9.5 will give 9.

So,

=><em> </em><u>19 / 2</u> / 2.0 + 2.5 * 6 / 2 + 0.5 * 4

=> 9 / 2.0 + 2.5 * 6 / 2 + 0.5 * 4

<em>(ii)followed by the second division operation. (i.e 9 / 2.0)</em>

=> From the result from step (i), the second division operation is now 9 / 2.0.

=> 9 / 2.0 = 4.5

So,

=> <u>9 / 2.0</u> + 2.5 * 6 / 2 + 0.5 * 4

=> 4.5 + 2.5 * 6 / 2 + 0.5 * 4

<em>(iii)followed by the first multiplication operation. (i.e 2.5 * 6)</em>

=> The first multiplication operation is given by 2.5 * 6

=> 2.5 * 6 = 15.0

So,

=> 4.5 + <u>2.5 * 6</u> / 2 + 0.5 * 4

=> 4.5 + 15.0 / 2 + 0.5 * 4

<em>(iv)followed by the third division operation. (i.e 15.0 / 2)</em>

=> The third division operation is given by 15.0 / 2

=> 15.0 / 2 = 7.5

So,

=> 4.5 + <u>15.0 / 2</u> + 0.5 * 4

=> 4.5 + 7.5 + 0.5 * 4

<em>(v)followed by the second multiplication operation. (i.e 0.5 * 4)</em>

=> The second multiplication operation is given by 0.5 * 4

=> 0.5 * 4 = 2.0

So,

=> 4.5 + 7.5 + <u>0.5 * 4</u>

=> 4.5 + 7.5 + 2.0

<em>(vi) followed by the first addition operation. (i.e 4.5 + 7.5)</em>

=> The first addition operation is given by 4.5 + 7.5

=> 4.5 + 7.5 = 12.0

So,

=> <u>4.5 + 7.5</u> + 2.0

=> 12.0 + 2.0

<em>(vii) lastly followed by the second addition operation. (i.e 12.0 + 2.0)</em>

=> The second addition operation is given by 12.0 + 2.0

=> 12.0 + 2.0 = 14.0

So,

=> <u>12.0 + 2.0</u>

=> 14.0

<em>Therefore, 19 / 2 / 2.0 + 2.5 * 6 / 2 + 0.5 * 4 = 14.0</em>

<h2>Note:</h2>

In Java, the order of precedence for arithmetic operators is;

=> /, * and %

=> followed by + and -

6 0
3 years ago
Given a list of integers. find the size of the list
dlinn [17]

The size of a list of integers can be found using python as follows;

size = len(list1)

<h3>How to find the size of a list using python?</h3>

The size of a list can be found using the len() function in python.

According to the question, the list is an integer.

Therefore, let's use an example below:

list1 = [1, 2, 1, 3, 6, 7, 8, 9, 4, 7, 8, 6, 4]

size = len(list1)

print(size)

Therefore,  the size of a list of integers can be found using the len() function in python.

learn more on python here: brainly.com/question/14989942

#SPJ1

6 0
2 years ago
Which of the following are the functions of an os?
cricket20 [7]
Manage the computer's resources, such as the central processing unit, memory, disk drives, and printers, (2) establish a user interface, and (3) execute and provide services for applications software.
6 0
3 years ago
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