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Contact [7]
3 years ago
10

a term to describe article that can be displayed in their entirety as opposed to abstract and reference only?​

Computers and Technology
1 answer:
Maurinko [17]3 years ago
7 0

Answer:

would it be term and tequnique?

Explanation:

oooooooo

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You are troubleshooting network connectivity issues on a workstation. which command would you use to request new ip
xxMikexx [17]

In the scenario in which you are troubleshooting network connectivity issues on a workstation the command that you should use in order to request new IP configuration information from a DHCP server is: ipconfig/renew. This command tells your computer to renew its current IP address lease with the router.

8 0
3 years ago
Exercise1 : Defining Circle type and Creating a Driver Circle class private members double radius double xPos double yPos public
asambeis [7]

Answer:

Aee explaination

Explanation:

1) class_circle.h

#include<iostream>

#include<cmath>

#include<iomanip>

#define PI 3.14159

using namespace std;

class circle

{

private:

double radius,xPos,yPos;

public:

double diameter();

double area();

double circumference();

double getRadius();

double getX();

double getY();

void setX(double x);

void setY(double y);

double distanceToOrigin();

bool intersect(const circle& otherCircle);

bool setRadius(double r);

};

class CircleDriver:public circle

{

private:

circle circ1;

circle circ2;

void obtainCircles();

void printCircleInfo();

public:

void run();

};

2) class_circle.cpp

#include "class_circle.h"

double circle::diameter()

{

return (radius * 2);

}

double circle::area()

{

return PI * radius * radius;

}

double circle::circumference()

{

return 2 * PI * radius;

}

double circle::distanceToOrigin()

{

return sqrt((xPos * xPos) + (yPos * yPos));

}

double circle::getRadius()

{

return radius;

}

double circle::getX()

{

return xPos;

}

double circle::getY()

{

return yPos;

}

void circle::setX(double x)

{

xPos = x;

}

void circle::setY(double y)

{

yPos = y;

}

bool circle::setRadius(double r)

{

if(r > 0)

{

radius = r;

return true;

}

else

{

radius = 0;

return false;

}

}

bool circle::intersect(const circle& otherCircle)

{

double dist1 = (radius - otherCircle.radius) * (radius - otherCircle.radius);

double dist2 = ((xPos - otherCircle.xPos) * (xPos - otherCircle.xPos)) + ((yPos - otherCircle.yPos)*(yPos - otherCircle.yPos));

double dist3 = (radius + otherCircle.radius) * (radius + otherCircle.radius);

if((dist1 <= dist2 ) && (dist2 <= dist3) && (dist1 < dist3))

return true;

else

return false;

}

void CircleDriver::obtainCircles()

{

double x,y,rad;

cout<<"Enter xPos yPos circle 1 :";

cin>>x>>y;

do

{

cout<<"\n\nEnter radius for circle 1 :";

cin>>rad;

}while(rad <= 0);

circ1.setX(x);

circ1.setY(y);

circ1.setRadius(rad);

cout<<"\n\nEnter xPos yPos circle 2 :";

cin>>x>>y;

do

{

cout<<"\n\nEnter radius for circle 2 :";

cin>>rad;

}while(rad <= 0);

circ2.setX(x);

circ2.setY(y);

circ2.setRadius(rad);

}

void CircleDriver::printCircleInfo()

{

cout<<setprecision(6)<<endl;

cout<<"\n\nInformation for Circle 1:"<<endl;

cout<<"location:( "<<circ1.getX()<<" ,"<<circ1.getY()<<" )"<<endl;

cout<<"diameter: "<<circ1.diameter()<<endl;

cout<<"area: "<<circ1.area()<<endl;

cout<<"circumference: "<<circ1.circumference()<<endl;

cout<<"distance from the origin: "<<circ1.distanceToOrigin()<<endl;

cout<<"\n\nInformation for Circle 2:"<<endl;

cout<<"location:( "<<circ2.getX()<<" ,"<<circ2.getY()<<" )"<<endl;

cout<<"diameter: "<<circ2.diameter()<<endl;

cout<<"area: "<<circ2.area()<<endl;

cout<<"circumference: "<<circ2.circumference()<<endl;

cout<<"distance from the origin: "<<circ2.distanceToOrigin()<<endl<<endl;

if(circ1.intersect(circ2))

cout<<"The circles intersect."<<endl;

else

cout<<"The circles does not intersect."<<endl;

}

void CircleDriver::run()

{

obtainCircles();

printCircleInfo();

}

3) main.cpp

#include "class_circle.h"

int main()

{

CircleDriver myDriver;

myDriver.run();

return(0);

}

Please refer below output for reference

Enter xPos yPos circle 1 :0.0 50.0

Enter radius for circle 1 :100.0

Enter xPos yPos circle 2 :50.0 0.0

Enter radius for circle 2 :100.0

Information for Circle 1:

location:( 0 ,50 )

diameter: 200

area: 31415.9

circumference: 628.318

distance from the origin: 50

Information for Circle 2:

location:( 50 ,0 )

diameter: 200

area: 31415.9

circumference: 628.318

distance from the origin: 50

The circles intersect.

Process returned 0 (0x0) execution time : 18.245 s

Press any key to continue.

8 0
3 years ago
Is there anyone willing to sign into my google classroom account and help with my work :( i had surgery on monday and have about
Soloha48 [4]

Answer:

yeah I can help u but how will I get ur email and password?

3 0
3 years ago
Read 2 more answers
The rules and guidelines for appropriate computer mediated communication are called ________. A. Social norms b. Etiquette c. Ne
horsena [70]

The rules and guidelines for appropriate computer mediated communication are called Netiquette.

<h3>What is Netiquette?</h3>

Netiquette, which is a  blend of  “net” and “etiquette,” refers to the polite  and appropriate behavior  when communicating with others online.

These rules are important as they help to improve  communication skills, prevent misconceptions, and encourage only socially acceptable behavior when working or  collaborating online.

Some of the DOs of Netiquette among others includes:

  • Being mindful of your tone
  • Use of  emoticons
  • Use of good grammar

Some of the DONTs among others includes:

  • Overuse of abbreviations
  • Unnecessary rants/Flaming
  • Overusing  caps

In conclusion Netiquette involves not doing what you would not do in person.

Learn more about Netiquette here:brainly.com/question/998689

3 0
2 years ago
Modify the statistics program from this chapter so that client programshave more flexibility in computing the mean and/ or stand
vampirchik [111]

Answer and Explanation:

Using Javascript:

function mean(nums){

var array_numbers= new array(nums);

var meanofNums= array_numbers.reduce()/array_numbers.length;

Console.log(meanofNums);

}

Function Std(nums){

var OurArray= new Array(nums);

var meanOfnums= mean(nums);

var i;

for(i=0; i<=OurArray.length; i++){

OurArray[i]= OurArray[i]-meanOfnums*OurArray[i]-meanOfnums;

}

var al_stdOfnums= OurArray.reduce()/OurArray.length;

var stdOfnums= Math. sqrt(al_stdOfnums);

Console.log(stdOfnums);

}

function meanStdDev (nums){

mean(nums);

Std(nums);

}

/*From the code above, we have defined functions and used them in the last function definition meanStdDev (nums), making for code reusability. In defining the functions, we have followed the formulas for calculating mean and standard deviations and implemented in that order. Notice how we used a for loop in std(nums) function definition to iterate through the elements of the array nums, squaring each value and reassigning a new value for each element(using index value) in the array. We then added these values in array using reduce method, dividing by array length and square rooting the value using the math object method sqrt().*/

8 0
3 years ago
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