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frosja888 [35]
3 years ago
12

What is the measure of EH!?!????? RUNNING OUT OF TIME

Mathematics
1 answer:
vladimir2022 [97]3 years ago
6 0
I think the answer is B.

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Step-by-step explanation: A function y=(x-10)(x-2) will have its zeros at x=10 and x=2. y=x²-12x+20.

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a bookstore has 780,000 and sales revenue in 2005 $190,000 2011 assuming a constant annual rate of decrease what is the predicte
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Answer5,90,000

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7 0
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83 tens times 2 tens
gizmo_the_mogwai [7]

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Step-by-step explanation:

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6 0
3 years ago
Hello I would really appreciate if someone could help me with this math question. I’m so confused
Katarina [22]

Answer:

  a. f = 17.5/c

  b. 8.75 N

Step-by-step explanation:

<h3>(a)</h3>

Inverse variation means one variable is proportional to the inverse of the other. The equation for that is ...

  f = k(1/c) . . . . . . force (f) is proportional to the inverse of distance (c)

We find the value of k using data given for a specific instance.

  3.5 N = k(1/(5 cm)) . . . . use the given values

  17.5 N·cm = k . . . . . . multiply by the denominator

Then the equation of interest is ...

  f = 17.5/c . . . . . . . where c is in cm, and f is in newtons

__

<h3>(b)</h3>

Using the above equation, we find the force to be ...

  f = 17.5/2 = 8.75 . . . . newtons

_____

<em>Additional comment</em>

We often look at several different kinds of proportionality:

  • y = kx . . . . direct
  • y = k(1/x) . . . . inverse
  • y = kx² . . . . proportional as the square
  • y = kx·z . . . . jointly proportional to x and z

and there are combinations of these, such as ...

  • y = kr²h . . . . jointly proportional to h and the square of r

You may have noticed that when x and y are inversely proportional, their product is a constant. y = k/x  ⇒  xy = k

__

We have left off the units of k in the problem above. Sometimes it is a good idea to retain them, or to pay close attention to what they are. This can avoid using the wrong measures for the variables.

  f = (17.5 N·cm)/(2 cm) = 8.75 N . . . . . units of cm cancel

4 0
2 years ago
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