Answer:
1/2
Step-by-step explanation:
We first find the least common multiple, which is 6. Therefore, we can multiply 1/3 x 2/2 (since 2/2 is equal to one and won't change the final amount) and get 2/6. 2/6+1/6=3/6, or 1/2.
I have an expression

floating around in my head; let's see if it makes sense.
The variance of binary valued random variable b that comes up 1 with probability p (so has mean p) is

That's for an individual sample. For the observed average we divide by n, and for the standard deviation we take the square root:

Plugging in the numbers,

One standard deviation of the average is almost 2% so a 27% outcome was 3/1.9 = 1.6 standard deviations from the mean, corresponding to a two sided probability of a bit bigger than 10% of happening by chance.
So this is borderline suspect; most surveys will include a two sigma margin of error, say plus or minus 4 percent here, and the results were within those bounds.
Answer:
2 kids plan to do cross country
Step-by-step explanation:
If you start with the tens it will mess up the problem