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TEA [102]
3 years ago
9

How do i solve 2/3+1/2

Mathematics
1 answer:
Vlad1618 [11]3 years ago
6 0

To solve this equation you will need common demoninators. So, find a number that both 3 and 2 can go into. They can both go into 6. Whatevr you do to the denominator, you have to do to the numerator. Since we multiplied 3 times 2 to get 6, we multiply the numerator 2 by 2 as well leaving us with 4/6. Do the same to the other fraction. 2 times 3 is 6, so 1 times 3 is 3. We are left with 4/6 and 3/6. Now we add! 4 + 3 is 7 so as an improper fraction it would be 7/6. As a mixed number and proper fraction it would be 1  1/6. So your answer is approximately 1  1/6. Hope this helped! Mark brainliest!

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Terry has 25 bills. He has ten-dollar bills and fifty-dollar bills
dexar [7]

Answer: He can have 12 fifty-dollars bills and 7 ten-dollar bills.

Step-by-step explanation:

12*50=700

7*10=70

      _____+

       770

3 0
3 years ago
A circle has its center at (6, –3). One point on the circle is (3, 1). Which is another point that lies on the circle?
nikdorinn [45]

Answer:

(4,0)

Step-by-step explanation:

4 0
3 years ago
Name the subsets of which the number 13 belongs to. If you can even just tell me how to find the subset that's great! :)
Mamont248 [21]
It also belongs to set of natural numbers.
6 0
2 years ago
Hem dibuixat tres rectangles. En el primer, la llargada mesura 3 cm més que l'amplada. El segon i tercer rectangle tenen unes di
quester [9]

Resposta:

Primer rectangle:

Amplada = 11

Longitud = 14

Segon rectangle:

Amplada = 12

Longitud = 15

Tercer rectangle:

Amplada = 13

Longitud = 16

Explicació pas a pas:

Donat que:

Primer rectangle:

Amplada = x

Longitud = x + 3

2n rectangle:

Augment de la dimensió d'1 cm respecte al primer rectangle;

Amplada = x + 1

Longitud = x + 4

3r rectangle:

Augment de la dimensió de 2 cm respecte al primer rectangle;

Amplada = x + 2

Longitud = x + 5

Suma dels tres perímetres del rectangle:

Perímetre d'un rectangle: 2 (l + O)

Primer rectangle:

2 (x + x + 3) = 2 (2x + 3) = 4x + 6

2n:

2 (x + 1 + x + 4) = 2 (2x + 5) = 4x + 10

3r:

2 (x + 2 + x + 5) = 2 (2x + 7) = 4x + 14

Suma de perímetres = 162

(4x + 6 + 4x + 10 + 4x + 14) = 162

12x + 30 = 162

12x = 162 - 30

12x = 130

x = 11

Per tant,

Primer rectangle:

Amplada = 11

Longitud = 11 + 3 = 14

2n rectangle:

Amplada = 11 + 1 = 12

Longitud = 11 + 4 = 15

3r rectangle:

Amplada = 11 + 2 = 13

Longitud = 11 + 5 = 16

8 0
3 years ago
IMPORTANT PLEASE!! 10 POINTS :)
s344n2d4d5 [400]

Answer:

The domain is all the possible inputs for this function. The range is all the possible outputs for this function.

The line starts at the <em>x-value</em> of 0 and ends at the <em>x-value</em> of 12. Therefore, your domain is D: [0, 12].

The line starts at the <em>y-value</em> of 9000 and ends at the <em>y-value</em> of 0. Therefore, your range is R: [0, 9000].

5 0
3 years ago
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