I need help please

Please help me answer this question and show work

maria [59]

Answer:

c=45 and A=145

M=15 and L=115

Step-by-step explanation:

6 0

2 years ago

in three plays of a football game, there is a gain of 4 yards, a loss of 9 yards, and a gain of 15 yards. What number can you us

Aloiza [94]

We can use minus(-) sign i.e. -9 to represent loss of 9 yards.

<h3>Write the difference between gain and loss.</h3>

The word “gain” implies “acquiring something”.

Gain means to acquire something one desires especially because of one’s efforts.

Gain means to get something additional, for example, to gain more speed, to gain more weight.

We can denote gain by using plus(+) sign before the given number.

“Loss” generally means “to lose something one already has.”

Loss means the deprivation from keeping something, for example, bearing the loss of a theft.

It refers to something which is lost, for example, the theft of jewelry was a great loss.

We can denote loss by using minus(-) sign before the number.

In the given question it is said that there is gain of 4 yards, loss of 9 yards and gain of 15 yards.

It is asked that how would we represent 9 yards loss.

We know that we use minus(-) sign to represent loss.

So we can represent loss of 9 yards by writing it as -9.

To learn more about gain and loss,

brainly.com/question/18281564

#SPJ9

5 0

1 year ago

Which Property Is Shown? k*(7-9)=(k*7)-(k*9) a. Commutative Property of Multiplication b. Multiplicative Property c. Multiplicat

Gnesinka [82]

D. Distributive Property

The distributive property allow you to multiply a sum by multiplying each addend separately.

6 0

3 years ago

Help!!! please what's is the figure

S_A_V [24]

Hello from MrBillDoesMath!

Answer:

108 cm^2

Discussion:

The area of the logo =

area of Trapezoid on top (I) + area of triangle on bottom (II)

I = (1/2) h ( b1 + b2) h = altitude, b1, b2 = bases

= (1/2) 6 ( 6 + 12)

= (1/2) 6 ( 18)

= 54

II = (1/2) b h

= (1/2) (12) ( 15 - 6) => altitude of triangle = 15 - 6 NOT (1/2) 15

= 54

I + II= 54 + 54 = 108

Thank you,

MrB

3 0

2 years ago

Read 2 more answers

Complete the square and write in standard form. Show all work.What would be the conic section:CircleEllipseHyperbolaParabola

mote1985 [20]

ANSWER

This is an ellipse. The equation is:

$\frac{(x-1)^2}{3^2}+\frac{(y+4)^2}{4^2}=1$

EXPLANATION

We have to complete the square for each variable. To do so, we have to take the first two terms and compare them with the perfect binomial squared formula,

$(a+b)^2=a^2+2ab+b^2$

For x we have to take 16x² and -32x. Since the coefficient of x is not 1, first, we have to factor out the coefficient 16,

$16x^2-32x=16(x^2-2x)$

Now, the first term of the expanded binomial would be x and the second term -2x. Thus, the binomial is,

$(x-1)^2=x^2-2x+1$

To maintain the equation, we have to subtract 1,

$16(x^2-2x+1-1)=16((x-1)^2-1)=16(x-1)^2-16$

Now, we replace (16x² - 32x) from the given equation by this equivalent expression,

$16(x-1)^2-16+9y^2+72y+16=0$

The next step is to do the same for y. We have the terms 9y² + 72y. Again, since the coefficient of y² is not 1, we factor out the coefficient 9,

$9y^2+72y=9(y^2+8y)$

Following the same reasoning as before, we have that the perfect binomial squared is,

$(y+4)^2=y^2+8y+16$

Remember to subtract the independent term to maintain the equation,

$9(y^2+8y)=9(y^2+8y+16-16)=9((y+4)^2-16)=9(y+4)^2-144$

And now, as we did for x, replace the two terms (9y² + 72y) with this equivalent expression in the equation,

$16(x-1)^2-16+9(y+4)^2-144+16=0$

Add like terms,

$\begin{gathered} 16(x-1)^2+9(y+4)^2+(-16-144+16)=0 \\ 16(x-1)^2+9(y+4)^2-144=0 \end{gathered}$

Add 144 to both sides,

$\begin{gathered} 16(x-1)^2+9(y+4)^2-144+144=0+144 \\ 16(x-1)^2+9(y+4)^2=144 \end{gathered}$

As we can see, this is the equation of an ellipse. Its standard form is,

$\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1$

So the next step is to divide both sides by 144 and also write the coefficients as fractions in the denominator,

$\begin{gathered} \frac{16(x-1)^2}{144}+\frac{9(y+4)^2}{144}=\frac{144}{144} \\ \\ \frac{(x-1)^2}{\frac{144}{16}}+\frac{(y+4)^2}{\frac{144}{9}}=1 \end{gathered}$

Finally, we have to write the denominators as perfect squares, so we identify the values of a and b. 144 is 12², 16 is 4² and 9 is 3²,

$\frac{(x-1)^2}{(\frac{12}{4})^2}+\frac{(y+4)^2}{(\frac{12}{3})^2}=1$

Note that we can simplify a and b,

$\frac{12}{4}=3\text{ and }\frac{12}{3}=4$

Hence, the equation of the ellipse is,

$\frac{(x-1)^2}{3^2}+\frac{(y+4)^2}{4^2}=1$

3 0

11 months ago