Answer:
D. Yes, because the frequencies start low, proceed to one or two high frequencies, then decrease to a low frequency, and the distribution is approximately symmetric.
Step-by-step explanation:
Hello!
The given frequency distribution for temperatures.
To see if the distribution appears to have a normal distribution you have to draw a histogram using the information. Check attachment.
As you can see, the distribution appears symmetric, it starts low and proceeds to grow until it reaches its maximum point (f(4)=13) and then starts to decrease to low frequencies. The right tail decreases a little more than the left one but it is almost symmetrical.
I hope this helps!
Answer:1/3
Step-by-step explanation:
gradient equals
![\frac{Y2-Y1}{X2-X1}](https://tex.z-dn.net/?f=%5Cfrac%7BY2-Y1%7D%7BX2-X1%7D)
=![\frac{5-3}{10-4}](https://tex.z-dn.net/?f=%5Cfrac%7B5-3%7D%7B10-4%7D)
=![\frac{2}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B6%7D)
=![\frac{1}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D)
I'd say that, if the angles S and U are equal, as the SV and UV segments move towards each other, they meet at vertex V, the angles they make, angle SVT and UVT, have to be equal, because the side TV is shared by both, and has the same direction.
now, side TV is on both triangles, and is shared by both, so is the same length, so TV on one triangle is equal to TV on the other
check the picture below
so, you have one Angle, another Angle, and then a Side
A A S
The answer is 6hours in 122 minutes do umknow