Question

If a football is thrown upward, its height above the

Answer 1

Answer:

a) s = -16$t^{2}$ + 192t + 96

b) Height of the football after 2 seconds is 448 feet.

ii. The football would not hit the ground after 2 seconds.

Step-by-step explanation:

Given:

s = -16$t^{2}$ + $V_{o}$t + $s_{o}$

where: s is the height of the football above the ground, t is the time, $V_{o}$ is the initial velocity and $s_{o}$ is the initial height.

The height of the building = $V_{o}$ = 192 feet and the initial speed of the ball = $s_{o}$ = 96 feet per second, then;

s = -16$t^{2}$ + 192t + 96

a) The polynomial is given as:

s = -16$t^{2}$ + 192t + 96

b) The height of the football when t = 2 seconds is;

s = -16(2) + 192(2) + 96

 = -32 + 384 + 96

 = -32 + 480

s = 448

The height of the football when t = 2 seconds is 448 feet.

ii. The football would not hit the ground after 2 seconds.