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vfiekz [6]
3 years ago
5

Find the y-intercept for the line represented by this equation -2y=4x+8

Mathematics
2 answers:
ExtremeBDS [4]3 years ago
7 0
OK.........
The y-intercept of -2y=4x+8 would be
-4 
and the slope of that would be 
-2 

H0P3 It H3LPS :)
ad-work [718]3 years ago
6 0
The y intercept = -4

Also, the slope of the line (if needed) is -2.



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Round 533,736 to the nearest thousand
tresset_1 [31]
The thousand if this number is 533,736.
So we need to round by that place. 
The answer is 534,000 because since the 7 is greater than 5, we need to round up. 

3 0
3 years ago
8k + 2m = 3m + k<br><br> Solve for k
mina [271]
Minus both sides by 2m
8k = 3 m - 2m + k \\ 8k = m + k
Minus both sides by k
7k = m
Divided both sides by 7
k =  \frac{m}{7}
6 0
3 years ago
Check my last question is u want 10 pts
larisa [96]
Ok..................
4 0
3 years ago
A car is traveling at 47 mph. If its tires have a diameter of 27 inches, how fast are the car's tires turning? Express the answe
Amiraneli [1.4K]

Answer:

3676.44 rad/min

Step-by-step explanation:

It is a problem about the angular speed of the car's wheel.

You can calculate the angular speed by using the following formula, which relates the tangential speed of the wheels (the same as the speed of the car) with the angular speed:

\omega=\frac{v}{r}    ( 1 )

v: speed of the car = tangential speed of the wheels = 47mph

r: radius of the wheels = 27/2 in = 13.5 in

you change the units of the speed:

47mph*\frac{63360in}{1mille}*\frac{1h}{60min}=49632\frac{in}{min}

next, you replace the values of v and r in the equation (1):

\omega=\frac{v}{r}=\frac{49632in/min}{13.5in}=3676.44\frac{rad}{min}

Then, the car's tires are turning with an angular speed of 3676.44 rad/min

8 0
3 years ago
a manufacturer has determined that if his company sells x items per day then their profit is given by P=-x^2+ 700 x-10000 euros.
Radda [10]

Answer:

15

Step-by-step explanation:

To find the minimum amount of items, x, that need to be sold for the manufacturer to make a profit, we can use the quadratic formula

x = \frac{-b+\sqrt{b^{2}-4ac } }{2a}; x=  \frac{-b-\sqrt{b^{2}-4ac } }{2a}

x= \frac{-700+\sqrt{700^{2}-4(a)(-10000) } }{2(1)}; x= \frac{-700-\sqrt{700^{2}-4(a)(-10000) } }{2(1)}

x= \frac{-700+\sqrt{530000} }{2}; x= \frac{-700-\sqrt{530000} }{2}

x=\frac{-700+100\sqrt{53} }{2}; x=\frac{-700-100\sqrt{53} }{2};

x=-350 + 50\sqrt53 = 14.005; x = -350 - 50\sqrt53 = -714.005

In context of the problem, we can only rely on the positive value, as the negative value would lead to a loss of profit.

(-714.005)^2+700(-714.005)-10000=-0.360

Furthermore, we must round to the nearest whole number, as you cannot make part of an item.

Lastly, if you were to plug in 14 into the equation for Profit, you would still have a negative number (i.e. a negative profit), thus requiring the manufacturer to make no less than 15 items to make a profit:

(14)^2+700(14)-10000=-4\\\\(15)^2+700(15)-10000=725

3 0
2 years ago
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