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3 years ago

What is 3 11/12 as a decimal?

Mathematics

2 answers:

aleksandr82 [10.1K]3 years ago

4 0

That’s the answer or u can but a bar on the 6 because it’s repeating 3.916666666

STatiana [176]3 years ago

3 0

Answer:

3.9167, or 3.916 repeated

Step-by-step explanation:

if you can't use simple math to turn a fraction into a decimal divide the numerator by the denominator with a calculator and if asked round to the nearest number.

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The length of a rectangle field if 7/5 of its width. if the perimeter of the field is 240 meters, what are the length and width

trasher [3.6K]

Perimeter of any figure is all its sides summed up

for a rectangle, with two equal pairs, that means, length + length + width + width or 2length + 2width, or 2(length + width)

but we know the length is 7/5 the width

width = w
perimeter = P

$\bf P=2\left(\frac{7}{5}w +w \right)\qquad P=240\implies 240=2\left(\frac{7}{5}w +w \right)
\\\\\\
120=\frac{7}{5}w +w\impliedby \textit{let's multiply both sides by 5}
\\\\\\
600=7w+5w\implies 600=12w\implies \cfrac{600}{12}=w$

and the length is 7/5 of that

7 0

3 years ago

How do you solve for x

kenny6666 [7]

Step-by-step explanation:

x+90+4x-75=180

add all the sides together and since its a triangle they equal to 180

7 0

3 years ago

Can someone please help me with these 50 points I just don't get it I need help?

Tanzania [10]

Answer: I think the first one is A. and the next one is B

Step-by-step explanation:

4 0

3 years ago

You have a six-sided die that you roll once. Let Ri denote the event that the roll is i. Let G j denote the event that the roll

Misha Larkins [42]

Answer:

a. $P (R3 | G1)=\frac{1}{5}$

b. $P (R6| G3)= \frac{1}{3}$

c. $P(G3|E)=\frac{2}{3}$

d. $P (E|G3)=\frac{2}{3}$

Step-by-step explanation:

The sample space associated with the random experiment of throwing a dice is is the equiprobable space {R1, R2, R3, R4, R5, R6}. Then,

a. The conditional probability that 3 is rolled given that the roll is greater than 1? $P (R3 | G1) = \frac{P (R3\bigcap G1)}{P(G1)} = \frac{1/6}{5/6} = \frac{1}{5}$

b. What is the conditional probability that 6 is rolled given that the roll is greater than 3? $P (R6| G3) = \frac{P (R6\bigcap G3)}{P(G3)} = \frac{1/6}{3/6} = \frac{1}{3}$

c. What is P [GIE], the conditional probability that the roll is greater than 3 given that the roll is even? $P(G3|E) = \frac{P (G3\bigcap E)}{P(E)} = \frac{2/6}{3/6} = \frac{2}{3}$

d. Given that the roll is greater than 3, what is the conditional probability that the roll is even? $P (E|G3) = \frac{P (E\bigcap G3)}{P(G3)} = \frac{2/6}{3/6} = \frac{2}{3}$

6 0

3 years ago

In the parallelogram shown, find x.

Olin [163]

The side with all the 9s and x is 12 just like its opposite side because this is a parallelogram. We can write the equation to add up the three segments; the ones on the left and right are 9-x:

9-x + x + 9-x = 12

18 - x = 12

x = 6

4 0

3 years ago