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svetoff [14.1K]
2 years ago
11

Segment AB=2x+8 and segment BD=4x+12. If segment AD=86, what is the value of x?

Mathematics
1 answer:
ValentinkaMS [17]2 years ago
7 0

Answer: x=11

Step-by-step explanation:

AB+BD=AD

(2x+8) + (4x+12) = 86

Combine like terms.

6x + 20 = 86

Minus 20 from both sides to get x by itself.

6x = 66

Divide both sides by x to find the value of a singular x.

x= 11

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The perimeter of a rectangular is 58 cm. The length is 5 more than twice the width.
riadik2000 [5.3K]
<h3>Answer:</h3>

a) l = 5 + 2w

b) P = 2(l +w) = 2(5 +2w +w)

c) w = 8 cm, l = 21 cm

<h3>Explanation:</h3>

a) Using w for width, twice the width is 2w, and 5 more than that is 5+2w. This is your expression for l:

... l = 5 + 2w

b) The perimeter is the sum of the lengths of all sides, so is the sum of twice the length and twice the width.

... P = 2(l +w) = 2(5 +2w + w) . . . . substituting for l using the expression of (a)

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... 58 = 2(5 +3w) = 10 + 6w . . . . . collect terms, eliminate parentheses

... 48 = 6w . . . . . . . . . . . . . . . . . . subtract 10

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2 years ago
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