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Anestetic [448]
3 years ago
7

To test a customer’s internet connection, a tech records how long it takes five different websites to load (in seconds). The tim

es are 4.5, 3.8, 2.9, 3.2, and 2.3. What is the average (mean)?
Mathematics
2 answers:
Vladimir [108]3 years ago
8 0

Answer: 3.34 seconds

4.5+3.8+2.9+3.2+2.3=16.7

Then I divided the total by the number of times 5/16.7=3.34 seconds

Oksana_A [137]3 years ago
6 0

Answer:

14.86

Step-by-step explanation:

4.5+ 3.8+ 3.2 +2.3=16.7 divided by 5 which I got from how many numbers I added =14.86

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30 POINTS TO ANSWER!!!!!
Ede4ka [16]

Answer:

35

y = -4(-8) +3

y= 35

yea

that is the out put so 35

3 0
3 years ago
Lena purchased a prepaid phone card for $20. Long distance calls cost 21 cents a minute using this card, Lena used her card only
slega [8]

<u>Answer:</u>

37 minutes

<u>Step-by-step explanation:</u>

Lena has 20 dollars. 20 - 12.23 = 7.77

Lena has $7.77 dollars left.

We divide this by .21 to see how many minutes her call was.

7.77 ÷ .21 = 37

Rate as Brainliest and Thanks plz

5 0
3 years ago
Need some help please ASAP
zlopas [31]

Answer:

The answer is 11d = 121c


5 0
4 years ago
Read 2 more answers
Finding Derivatives Implicity In Exercise,Find dy/dx implicity.<br> x2e - x + 2y2 - xy = 0
Klio2033 [76]

Answer:

the question is incomplete, the complete question is

"Finding Derivatives Implicity In Exercise,Find dy/dx implicity . x^{2}e^{-x}+2y^{2}-xy"

Answer : \frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}

Step-by-step explanation:

From the expression  x^{2}e^{-x}+2y^{2}-xy" y is define as an implicit function of x, hence we differentiate each term of the equation with respect to x.

we arrive at

\frac{d}{dx}(x^{2}e^{-x )+\frac{d}{dx} (2y^{2})-\frac{d}{dx}xy=0\\

for the expression \frac{d}{dx}(x^{2}e^{-x}) we differentiate using the product rule, also since y^2 is a function of y which itself is a function of x, we have

(2xe^{-x}-x^{2}e^{-x})+4y\frac{dy}{dx}-x\frac{dy}{dx} -y=0\\\\(2-x)xe^{-x}+(4y-x)\frac{dy}{dx}-y=0 \\.

if we make dy/dx  subject of formula we arrive at

(4y-x)\frac{dy}{dx}=y-(2-x)xe^{-x}\\\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}

5 0
4 years ago
Find the height of a cylinder with a volume of 36piecm and a bad with a radius of 3cm
Fudgin [204]

Step-by-step explanation:

V=pi×r^2×h

36pi =pi × (3)^2 × h

36pi ÷ pi×9 = h

4cm^2 = h

6 0
3 years ago
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