What is the initial value of the equation shown?
2 answers:
Answer:
Option C
Step-by-step explanation:
we know that
The initial value is the value of the function when the value of x is equal to zero
The initial value is the y-intercept of the function
In this problem we have
-----> equation of the line into slope intercept form
therefore
-----> the slope
----> the y-intercept
The initial value is
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Answer:
y = -(5/2)x -2
Explanation:
The general formula for a straight line is y – mx + b.
The image below shows the graph of the line.
Step 1. <em>Calculate the slope</em>.
Slope = m = Δy/Δx = (y₂-y₁)/(x₂-x₁)
x₁ = 0; y₁ = -2
x₂ = -2; y₂ = 3 Calculate m
m = [3-(-2)]/(-2-0)
m = (3+2)/(-2)
m = 5/(-2)
m = -5/2
Step 2. <em>Calculate the y-intercept </em>
When x = 0, y = 2.
The y-intercept (b) is at y = -2
Step 3. <em>Write the equation </em>for the graph
y = mx + b
y = -(5/2)x - 2
Times both sides b 2
2V=(bh)H
remember associative property
(ab)c=a(bc)
and
ab=ba
so
(bh)H=h(bH)
2V=h(bH)
divide both sides by bH
2V=(bh)H
remember associative property
(ab)c=a(bc)
and
ab=ba
so
(bh)H=h(bH)
2V=h(bH)
divide both sides by bH
Given:
The figure of a right triangle. and perpendicular = 12.
To find:
The measure of angle y.
Solution:
In a right angle triangle,
In the given right angle triangle,
Therefore, the measure of angle y is .