In the triangles,BC is congruent to RS and AC is congruent to TS If RT is greater than BA, which correctly compares angles C and
S?
2 answers:
Answer:
Angle S > Angle C
Step-by-step explanation:
Given that in the triangles,BC is congruent to RS and AC is congruent to TS.
If RT =BA we have the two triangles congruent by SSS axiom
Hence by cpct property the two angles C and S would be equal
But RT>BA
Hence angle opposite RT must be greater than angle opposite BA
i.e. Angle S>Angle C
The comparison of angles C and S gives that
Angle C is less than angle S
The answer is B i just took the test m∠C < ∠S
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