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Gnom [1K]
4 years ago
9

The structure of adenosine triphosphate (ATP) is shown here. Which statement best explains how energy stored in the chemical bon

ds of ATP can be released.
SAT
1 answer:
Nadusha1986 [10]4 years ago
3 0
<h2>Answer:</h2>

When the bond between the second and third phosphate is broken down in different cellular processes huge amount of energy like 7.3 K cal is released.

<h3>Explanation:</h3>
  • ATP is the energy currency for the cells. Cells produce this currency in mitochondria via respiration.
  • As the energy is stored in the electrons involved in the boding between Gama phosphate and beta phosphate.
  • Formation of this energy requires a huge amount of energy and its breakdown also release that energy.
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D. Plant - atmosphere
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4 years ago
Which of the following is true of open systems of prisons
masya89 [10]

The truth about open systems of prisons is that they interact with the government and other groups.

<h3>What is an open system of prisons?</h3>

Open system of prisons is the type of jail that the people that are jailed have the ability to go on unsupervised in the prison yard..

This is unlike the closed system that has very strict supervision by the warders. They are able to interact with organizations and other people.

In this system those that are serving jail terms are able to get employed. This is because they have more freedom since they are not locked up in cells.

They are able to also attend workshops in the prisons. This is one reason why a lot of people in jail are able to learn skills, get educated and also earn cash while serving

The people that serve here are those that do not have the tendency of being high risks in such areas

Read more on American prison system  here: brainly.com/question/12316203

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5 0
2 years ago
A typical neutron star has a mass of about 1. 5msun and a radius of 10 kilometers
Triss [41]

How thick a layer would Earth form as it wraps around the neutron star’s surface is: 6.67 10⁻³ m.

<h3>Density of the Neutron star</h3>

Density

ρ = m / V

Where:

ρ= density

m = mass of the planet 5.98 10²⁴ km

V =volume of the spherical layer

Volume of a sphere

Volume = 4/3 π r³

Mass = 1.5 = 1.5 1,991 10³⁰

Mass= 2.99 10³⁰ kg

Density:

ρ = 2.99 10³⁰ / [4/3 π (10 10³)³]

ρ is = 7.13 10 17 kg / m³

V = 5.98 10²⁴ / 7.13 10¹⁷

V = 8,387 10⁶ m³

Thickness of the layer

V = 4π r² e

e = V / 4π r

e = 8,387 10⁶ / [4π (10 10³)²]

e = 6.67 10⁻³ m

Inconclusion how thick a layer would Earth form as it wraps around the neutron star’s surface is: 6.67 10⁻³ m.

Learn more about Density of the Neutron star here:brainly.com/question/15700804

3 0
2 years ago
What can you learn from the heading of a court case?.
ANTONII [103]

Answer:

we learn from court case law is blind. alaways take way of law never do any criminal activities

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A student pulls a block over a rough surface with a constant force fp that is at an angle θ above the horizontal, as shown above
Lesechka [4]
The force of friction between the block and surface will decrease.
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