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pishuonlain [190]
3 years ago
7

How do I solve this ?

Mathematics
1 answer:
Allisa [31]3 years ago
4 0
\left[\begin{array}{cc}3&6\\-1&-3\\-5&-1\end{array}\right] + \left[\begin{array}{cc}0&-1\\6&0\\2&3\end{array}\right] = \left[\begin{array}{cc}3+0&6-1\\-1+6&-3+0\\-5+2&-1+3\end{array}\right] = \left[\begin{array}{cc}3&5\\5&-3\\-3&2\end{array}\right]

-5\left[\begin{array}{ccc}5&6&-4\\4&-2&-1\end{array}\right] =\left[\begin{array}{ccc}-5(5)&-5(6)&-5(-4)\\-5(4)&-5(-2)&-5(-1)\end{array}\right]\\=\left[\begin{array}{ccc}-25&-30&20\\-20&10&5\end{array}\right]

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3 years ago
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Okay, so a general rule for finding perpendicular lines in the form of y = mx + b is y = (-1/m) + b.
First, let's ignore b (-7) because we're going to find that later.
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Alright, so now let's plug in the values. They are in the form of (x,y), so let's plug them in accordingly.

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3 years ago
A number is called evil if it has 666 in it. How many 7 digit numbers are evil?
defon

Step-by-step explanation:

There are 5 different positions of 666:

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The forward dashes represent any number from 0 to 9.

Case 1: "666////"

Number of ways = 10⁴ = 10,000.

Case 2: The other positions.

Since the 1st forward dash cannot be 0 (leading digit),

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Number of ways for all 4 positions = 9,000 * 4 = 36,000.

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