Question

PLEASE HELP, DUE AT MIDNIGHT >>>>>

Answer 1

Answer:

BELOW

Step-by-step explanation:

7.

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}\\\\\left(x_1,\:y_1\right)=\left(-8,\:-11\right),\:\left(x_2,\:y_2\right)=\left(17,\:4\right)\\\\m=\frac{4-\left(-11\right)}{17-\left(-8\right)}\\\\m = \frac{4+11}{17+8}= \frac{15}{25} \\\mathrm{Refine}\\\\m=\frac{3}{5}$

8.

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}\\\\\left(x_1,\:y_1\right)=\left(10,\:-15\right),\:\left(x_2,\:y_2\right)=\left(13,\:-17\right)\\\\m=\frac{-17-\left(-15\right)}{13-10}\\\\m = \frac{-17+15}{13-10}\\ \\m = \frac{-2}{3}\\ \\Simplify\\m=-\frac{2}{3}$

9.

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}\\\\\left(x_1,\:y_1\right)=\left(-6,\:-7\right),\:\left(x_2,\:y_2\right)=\left(5,\:-7\right)\\\\m=\frac{-7-\left(-7\right)}{5-\left(-6\right)}\\\\m = \frac{-7+7}{5+6}\\ \\m = \frac{0}{11}\\ \\Simplify\\m=0$

10.

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}\\\\\left(x_1,\:y_1\right)=\left(-4,\:-3\right),\:\left(x_2,\:y_2\right)=\left(2,\:-9\right)\\\\m=\frac{-9-\left(-3\right)}{2-\left(-4\right)}\\\\m = \frac{-9+3}{2+4}\\ \\m = \frac{-6}{6} \\\\Simplify\\m =-1$

11.

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}\\\\\mathrm{When\:}y_1\ne \:y_2\mathrm{\:and\:}\:x_1=x_2\mathrm{\:the\:slope\:is\:}\infty \\\\m = \infty$

12.

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}\\\\\left(x_1,\:y_1\right)=\left(-5,\:3\right),\:\left(x_2,\:y_2\right)=\left(19,\:-6\right)\\\\m=\frac{-6-3}{19-\left(-5\right)}\\\\m = \frac{-6-3}{19+5}\\ \\m = \frac{-9}{24}\\ \\Simplify\\m=-\frac{3}{8}$

13.

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}\\\\\left(x_1,\:y_1\right)=\left(-7,\:-12\right),\:\left(x_2,\:y_2\right)=\left(1,\:-16\right)\\\\m=\frac{-16-\left(-12\right)}{1-\left(-7\right)}\\\\m = \frac{-16+12}{1+7} \\\\m = \frac{-4}{8} \\\\Simplify\\m=-\frac{1}{2}$

14.

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}\\\\\left(x_1,\:y_1\right)=\left(-18,\:0\right),\:\left(x_2,\:y_2\right)=\left(-13,\:1\right)\\\\m=\frac{1-0}{-13-\left(-18\right)}\\\\m = \frac{1-0}{-13+18}\\ \\m = \frac{1}{5}$

15.

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}\\\\\left(x_1,\:y_1\right)=\left(1,\:-11\right),\:\left(x_2,\:y_2\right)=\left(-2,\:-4\right)\\\\m=\frac{-4-\left(-11\right)}{-2-1}\\\\m = \frac{-4+11}{-2-1}\\ \\m = \frac{7}{-3} \\\\Simplify\\m=-\frac{7}{3}$