All the numbers in this range can be written as

with

and

. Construct a table like so (see attached; apparently the environment for constructing tables isn't supported on this site...)
so that each entry in the table corresponds to the sum of the tens digit (row) and the ones digit (column). Now, you want to find the numbers whose digits add to perfect squares, which occurs when the sum of the digits is either of 1, 4, 9, or 16. You'll notice that this happens along some diagonals.
For each number that occupies an entire diagonal in the table, it's easy to see that that number

shows up

times in the table, so there is one instance of 1, four of 4, and nine of 9. Meanwhile, 16 shows up only twice due to the constraints of the table.
So there are 16 instances of two digit numbers between 10 and 92 whose digits add to perfect squares.
Answer:
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Step-by-step explanation:
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Y= -x/3+21 if you’re solving for y
16%
if you multiply 25 grams buy 4 you get 100 (100%) then you mulitply 4 by 4 which gives you 16 (16%)
I first converted 23 ft to inches by multiplying by 12
23 ft= 276 in
I then added the half inch so it became 276.5 inches
converting back to ft, by dividing by 12
276.5 in= 23.04 ft