Please, use " ^ " to denote exponentiation: p(t) = t^2 + 5t + 6.
To find the critical points, differentiate p(t) with respect to t, set the result = to 0, and then solve the resulting equation for t:
p '(t) = 2t + 5 = 0
Solving for t: 2t = -5, and so t = -5/2. (-5/2, p(-5/2)) is the critical point. That evaluates to (-5/2, -0.25). This happens to be the vertex of a parabola that opens up.
2x+3=17
subtract 3 from each side
2x+3 -3 = 17 -3
2x = 14
divide by 2 on each side
2x/2 = 14/2
x = 7
Answer:
5/2
Step-by-step explanation:
Substitute -3 to x
(-3)^2 + 4(-3) + 1
9 - 12 + 1
= -2
