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Step2247 [10]
3 years ago
13

Write an equation (a) in slope intercept form and (b) in standard form for the line passing through (2,7) and perpendicular to 3

x + 5y = 1
Mathematics
1 answer:
romanna [79]3 years ago
4 0

Answer:

Step-by-step explanation:

Solve 3x + 5y = 1 for y to obtain the slope of the given line:

5y = -3x + 1, or y = (-3/5)x + 1.

Any line perpendicular to this one has the slope which is the negative reciprocal of (-3/5):  That would be 5/3.

The desired line has slope 5/3 and passes through (2, 7);

Adapt y = mx + b by substituting the known values, to find b:

7 = (5/3)(2) + b.  The LCD is 3, so multiply each term by 3 to eliminate the fractional coefficient:

21 = 10 + 3b, or 11 = 3b.  Then b = 11/3, and the desired equation in slope intercept form is

y = (5/3)x + 11/3

To obtain the standard form, multiply all three terms by 3 again:

3y = 5x + 11, or

5x + 11 - 3y = 0, or

5x - 3y + 11 = 0

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We can see that a and b are parallel, and c and e are parallel, so the correct option is E.

<h3>Which line must be parallel?</h3>

On the diagram, we can see that the angles in the third quadrant of the intersections between a and c, and the intersections between b and c,  are the same angle.

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For the intersections with line d, we can see that this time the angle is on the fourth quadrant, so c and d are not parallel.

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2 years ago
Please help due in 6 minutes!!!!
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Answer:

hi

Step-by-step explanation:

Sorry u gonna fail cause I to dumb.

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hello

a) Pop as this is the one with the most CDs

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4 years ago
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