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ipn [44]
3 years ago
6

The shortest side of a fight triangle measures20 m. The lengths of the other two sides are censecutive odd integers. Find the le

ngth of the two aides
Mathematics
1 answer:
slamgirl [31]3 years ago
6 0
A² + b² = c²
20² + n² = (n+2)²
400+ n² = (n+2)(n+2)
400 + n²=n² + 2n + 2n +4
400 + n² = n² +4n +4
400 + n²-n² = n²-n² + 4n+4
400 = 4n + 4
400-4 = 4n +4-4
396 = 4n
396/4 = 4n/4
n= 99

20²+ 99² = (99+2)²
400 + 9801 =10201
10201=10201
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The correct response is ;
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Answer:

3.728 cm²

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Step-by-step explanation:

To built the envelope I am using a rectangular piece of material 28 m long and 12 m wide.  

Out of this material, I have to cut patches that are 1/12 the length and 2/15 the width of the whole material.

So, the length of the patches is 28 \times \frac{1}{12} = 2.33 m and the width of the patches is 12 \times \frac{2}{15} = 1.6 m.

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