The shortest side of a fight triangle measures20 m. The lengths of the other two sides are censecutive odd integers. Find the le
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Answer:
5n + 6 = -3n - 10
Solve for n:
Add 3n to both sides:
5n + 3n + 6 = -3n + 3n - 10
8n + 6 = -10
Subtract 6 from both sides:
8n + 6 - 6 = -10 - 6
8n = -16
Divide both sides by 8:
8n/8 = -16/8
n = -2.