The inverse function is equal to f-1(x) = (x - 1)/3 and the value at f-1(6) is equal to 5/3.
To find the inverse, you need to switch the f(x) and x in the equation. Then you can solve for the new f(x). The result will be the inverse (f-1)
f(x) = 3x + 1 ----> Switch f(x) and x
x = 3f(x) + 1 ----> Subtract 1
x - 1 = 3f(x) ----> Divide by 3.
f-1(x) = (x - 1)/3
Now that we have the inverse, we can plug 6 in to get the value at f-1(6).
f-1(x) = (x - 1)/3
f-1(6) = (6 - 1)/3
f-1(6) = 5/3
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Answer:
Choice B.
Step-by-step explanation:
We can eliminate each graph:
a). This is what is known as a step function. This is incorrect.
b). This is an exponential function because the graph is shaped like a geometric equation. This means that the rate of change is exponential. This is the correct choice.
c). This is an absolute value function. This is incorrect.
d). This is a graph of a polynomial. This does not represent an exponential function, which makes it incorrect.
Answer:
y = 12
Step-by-step explanation:
Looking at the large triangle
tan 30 = opposite / adjacent
tan 30 = 4 sqrt(3)/ y
Multiply each side by y
y tan 30 = 4 sqrt (3)
We know tan 30 = sqrt(3)/3
y * sqrt(3)/3 = 4 sqrt(3)
Multiply each side by 3/ sqrt(3) to isolate y
y * sqrt(3)/3 * 3/ sqrt(3) = 4 sqrt(3) * 3 /sqrt(3)
y = 12
To figure this out, divide the annual salary by the months in a year.
29,500/12=2458.33
Now divide that by half of the amount of weeks in month
2458.33/1.5=1638.88
So the answer is none of the above.
The table represents the relationship between the number of days, x, and the number of patients in a hospital showing flu symptoms.
100
18
13
Which statement is true?
The number of patients showing flu symptoms decreases at a constant rate as the number of days increases.
The number of patients showing flu symptoms decreases as the number of days increases but not at a constant rate.
The number of patients showing flu symptoms increases at a constant rate as the number of days increases.
The number of patients showing flu symptoms increases as the number of days increases but not at a constant rate.
