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3 years ago

Acellus help slope intercept

Mathematics

1 answer:

Serjik [45]3 years ago

3 0

Greetings.

The answer is y = 2x + 7.

Explanation:

If you are an expert in graph then you are able to find the slope without calculating. (Rise over Run by looking at the graph.)

We can also find the slope by calculating m-value.

$m=\frac{y_2-y_1}{x_2-x_1}$ ---> Rise Over Run

<em>But how are we gonna calculate if we don't have any two given ordered pairs?</em>

The answer is, we can just pick two ordered pairs that are part of the graph, or rather say that the graph passes through.

The graph passes through (-3,1) and (-2,3).

Then we can calculate the slope by using rise/run.

$m=\frac{3-1}{-2-(-3)}\\m=\frac{2}{-2+3}\\m=\frac{2}{1}\\m=2$

Thus, the slope is m = 2.

However, we are not done yet. We just only found out the slope. We need to find the y-intercept too.

From Linear Function - $y=mx+b$

Where m = slope and b = y-intercept.

Since b = y-intercept, we don't need to calculate/substitute x = 0. We simply find which number the graph has y-intercept at.

Which is (0,7), the y-intercept.

Then we substitute b = 7 as y-intercept.

Thus the answer is $y=2x+7$

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3 years ago

A Ferris wheel has a radius of 10 m, and the bottom of the wheel passes 1 m above the ground. If the Ferris wheel makes one comp

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Answer:

$y = 11 - 10cos(0.1\pi t)$

Step-by-step explanation:

Suppose at t = 0 the person is 1m above the ground and going up

Knowing that the wheel completes 1 revolution every 20s and 1 revolution = 2π rad in angle, we can calculate the angular speed

2π / 20 = 0.1π rad/s

The height above ground would be the sum of the vertical distance from the ground to the bottom of the wheel and the vertical distance from the bottom of the wheel to the person, which is the wheel radius subtracted by the vertical distance of the person to the center of the wheel.

$y = h_g + d_b = h_g + R - d_c$ (1)

where $h_g = 1$ is vertical distance from the ground to the bottom of the wheel, $d_b$ is the vertical distance from the bottom of the wheel to the person, R = 10 is the wheel radius, $d_c$ is the vertical distance of the person to the center of the wheel.

So solve for $d_c$ in term of t, we just need to find the cosine of angle θ it has swept after time t and multiply it with R

$d_c = Rcos(\theta(t)) = Rcos(\omega t) = 10cos(0.1\pi t)$

Note that $d_c$ is negative when angle θ gets between π/2 (90 degrees) and 3π/2 (270 degrees) but that is expected since it would mean adding the vertical distance to the wheel radius.

Therefore, if we plug this into equation (1) then

$y = h_g + R - d_c = 1 + 10 - 10cos(0.1\pi t) = 11 - 10cos(0.1\pi t)$