1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Oksi-84 [34.3K]
3 years ago
5

Last week, 108 cars received parking violations in the main university parking lot. Of these, 27 had unpaid parking tickets from

a previous violation. Assuming that last week was a random sample of all parking violators, find the 95 percent confidence interval for the percentage of parking violations that have prior unpaid parking tickets.
Mathematics
1 answer:
garik1379 [7]3 years ago
6 0

Answer:

95 percent confidence interval

[0.208,0.29166]

Step-by-step explanation:

First we identificate the sample proportion p = 27 /108, and we find the 95 percent confidence interval for P(population proportion) in this context the parking violations that have prior unpaid parking tickets.

Then α = 0.05 and 1 - α/2 = 0.975

Thus Z_{0.975} = 1.96

The 95 percent confidence interval is

[ p ± 1.96 \sqrt{\frac{p(1-p)}{n} } ]

[0.25  ± 1.96 \sqrt{\frac{0.25*0.75}{108} } ]

[0.208,0.29166]

You might be interested in
Students in a statistics class are conducting a survey to estimate the mean number of units students at their college are enroll
Papessa [141]

Answer:

The 95% confidence interval for the average number of units that students in their college are enrolled in is between 11.7 and 12.5 units.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 45 - 1 = 44

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 44 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2\frac{1.5}{\sqrt{45}} = 0.4

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 12.1 - 0.4 = 11.7 units

The upper end of the interval is the sample mean added to M. So it is 12.1 + 0.4 = 12.5 units

The 95% confidence interval for the average number of units that students in their college are enrolled in is between 11.7 and 12.5 units.

8 0
2 years ago
The side of the parallelogram in the figure above are given in cm.
GrogVix [38]

<em>solution</em>

<em>or</em><em>,</em><em> </em><em> </em><em> </em><em> </em><em>2 x + y </em><em>=</em><em> 5</em><em> y - </em><em>8</em><em> </em><em> </em><em> </em><em> </em><em> </em><em>being opposite side of </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>parallelogr</em><em>a</em><em>m</em><em> </em><em> </em><em> </em><em> </em><em> </em>

<em>or </em><em>,</em><em> </em><em>2x </em><em>=</em><em>5 y </em><em>-</em><em> </em><em>y</em><em> </em><em>-</em><em> </em><em>8</em>

<em>o</em><em>r</em><em>,</em><em> </em><em> </em><em>2x </em><em>=</em><em> </em><em>4 y -</em><em> 8</em>

<em>or</em><em>,</em><em> </em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>4</em><em>y</em><em> </em><em>-</em><em> </em><em>8</em><em>/</em><em>2</em>

<em>or</em><em>,</em><em>. </em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>2</em><em>y</em><em>-</em><em> </em><em>4</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>therefore</em><em>,</em><em> 2x + y</em><em> is equal to</em><em> </em><em>5 y - 8</em><em> </em><em>Being</em><em> the </em><em>opposite side of a parallelogram</em>

<em>now</em><em>,</em><em> </em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>3y + 2</em><em> </em><em>x</em><em> is equal to</em><em> 4</em><em>x</em><em> - 3</em><em> being opposite side of a parallelogram</em>

<em>or</em><em>,</em><em> </em><em>3y</em><em> </em><em>+</em><em> </em><em>2</em><em> </em><em>x-4x</em><em> </em><em>=</em><em> </em><em>-</em><em>3</em>

<em>or</em><em>,</em><em>. </em><em>3</em><em>y</em><em> </em><em>-2x</em><em> </em><em>=</em><em> </em><em>-</em><em>3</em>

5 0
3 years ago
45612.21μ (1x10^-6 / 1μ) = ??
Oliga [24]
First let's do parentheses. 1*10^-6 = .000001. Now divide that by one it equals the same thing. Now you need to multiply that by 45612.21. That equals 0.04561221μ
8 0
3 years ago
A toy rocket is launched vertically from 5 feet above ground level with an initial velocity of 112 feet per second. The height h
Masja [62]

Answer:

Step-by-step explanation:

a)The height h after t seconds is given by the equation h(t)=-16t^2+112t+5.

Where 5 represents 5feet above the ground and this is the height from which the rocket was launched.

The equation is a quadratic equation. The plot of this equation on a graph would give a parabola whose vertex would be equal to the maximum height travelled by the rocket.

The vertex of the parabola is calculated as follows,

Vertex = -b/2a

From the equation,

a = -16

b = 112

Vertex = - - 112/32= 3.5

So the rocket will attain maximum height at 3.5 seconds.

It will also take 3.5 seconds to reach the ground. This means it will take a total of 3.5 seconds + 3.5 seconds

= 7 seconds to hit the ground.

b) to find time it will take to be 100 feet above the ground,

-16t^2+112t-95 = 0

Using general quadratic equation formula,

a = -16

b = 112

c = -95

t = [-b+/-√b^2-4ac]/2a

t = [ -112 +/-√112^2-4×-16×-95]/16 × -2

= [-112 +/-√12544-6080]/-32

= (-112+80.4)/-32 or (-112-80.4)/-32

t = 0.9875 or t = 6.0125

So it will take 0.9875 or approximately 1 second to be 100 feet above the ground

7 0
3 years ago
Which shows the first step in the solution to the<br> equation log₂x + log₂(x - 6) = 4?
iren [92.7K]

log was used calculate big numbers before calculators

log is a re-arranged way to show a number with an exponent

example

log₂ 16 = 4 means 2^4 = 16

logx(Z) = y means x^y=Z

log(x-6)/log(2) + log(x)/log(2) = 4

(log(x-6)+ log(x))/log(2) = 4

(log(x-6)+ log(x)) = 4log(2)

(log(x-6)x) = log(16)

x=8

6 0
1 year ago
Other questions:
  • Solve the equation. <br> 5/6 x-4 = -2
    10·1 answer
  • Solve<br> 1/5x + 2/5x - 12 = -6.<br><br> The solution is x=<br><br> Please explain
    15·2 answers
  • PLEASE HELP!!!!!
    14·1 answer
  • Whats 2.3
    10·1 answer
  • What is the answer please?
    11·1 answer
  • Mike is catering a party. He plans on having 4 trays of 5 appetizers each on the buffet at the beginning of the party and will r
    5·2 answers
  • BRAINLIEST <br> Please help only three questions
    8·2 answers
  • Harriet bought a lot of new clothes and paid for them with a credit card. She doesn’t have the money to pay off the card yet, bu
    14·1 answer
  • Amelia played 8 games of cards with her grandpa. Her cousin played 4 times as many games as Amelia played. How many games did he
    5·2 answers
  • Differentiate the following with respect to x<br><br>irrelevant answers will be reported​
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!