Answer:
(6.8, 1.3)
Step-by-step explanation:
<u>Given</u>:
A(-3, -5), B(11, 4)
<u>Find</u>:
P such that AP/AB = 7/10
<u>Solution</u>:
Using the desired relation, we have ...
(P -A)/(B -A) = 7/10
10(P -A) = 7(B -A) . . . . . multiply by 10(B-A)
10P = 7B +3A . . . . . . . . add 10A to both sides
10P = 7(11, 4) +3(-3, -5) = (77 -9, 28 -15) = (68, 13)
P = (68, 13)/10 = (6.8, 1.3)
The point 7/10 of the way from A to B is (6.8, 1.3).
Mean = (2+4+6+5+2)/5 = 19/5 = 3.8
answer
<span>C. 3.8</span>
Answer:
9 years old.
Step-by-step explanation:
Since the ages of all of these students are being represented in relation to the middle student's age then we can create formulas for each student and then apply them to the formula for the sum of their ages and solve for the middle child's age (M) like so... (oldest child's age is represented by variable O and youngest child's age is represented by variable Y)
O = M + 6
Y = M - 3
30 = (M+6) + M + (M-3) ... combine like terms
30 = 3M + 3 ... subtract 3 from both sides
27 = 3M ... divide both sides by 3
9 = M
Now we know that the middle child is 9 years old.
You just have to set the denominator to zero and solve for x
1. find the area of the two triangles, including the shaded section. the formula for this is a=1/2bh
the height and base are both 24 inches. this is because you add the 10 from the side of the square to the 14 that is given
so:
a=1/2(24)(24)
a=(12)(24)
a=288 sq. inches
since there are two triangles, you would multiply the area by 2
a=2(288)
a=576 sq. inches
now, since you only need the unshaded section, you have to take away the shaded section, which is a square. to do this, you must calculate the area of the square and take it away from the area of both triangles.
a=576-(lw)
a=576- (10)(10)
a=576-100
a=476 sq. inches
that is your answer
