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salantis [7]
3 years ago
11

two containers filled with water are leaking. container A leaks at a rate of 2/3 gallon every 1/4 hour. Container B leaks at a r

ate of 3/4 gallon ever 1/3 hour. Determine which container is leaking water more rapidly

Mathematics
1 answer:
devlian [24]3 years ago
6 0

This might help u.....

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In P2, find the change-of-coordinates matrix from the basis B = {1 − 3t 2 , 2 + t − 5t 2 , 1 + 2t} to the standard basis of P2.
Serjik [45]

Complete Question:

In P2, find the change-of-coordinates matrix from the basis B = {1 − 3t² , 2+t− 5t² , 1 + 2t} to the standard basis C = {1, t, t²}. Then, write t² as a linear combination of the polynomials in B.

Answer:

The change of coordinate matrix is :

M = \left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right]

U = t² = 3 [1 − 3t²] - 2 [2+t− 5t²] + [1 + 2t]

Step-by-step explanation:

Let U =  {D, E, F} be any vector with respect to Basis B

U = D [1 − 3t²] + E [2+t− 5t²] + F[1 + 2t]..............(*)

U = [D+2E+F]+ t[E+2F] + t²[-3D-5E]...................(**)

In Matrix form;

\left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right] \left[\begin{array}{ccc}D\\E\\F\end{array}\right] = \left[\begin{array}{ccc}D+2E+F\\E+2F\\-3D-5E\end{array}\right]

The change of coordinate matrix is therefore,

M = \left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right]

To find D, E, F in (**) such that U = t²

D + 2E + F = 0.................(1)

E + 2F = 0.........................(2)

-3D -5E = 1........................(3)

Substituting eqn (2) into eqn (1 )

D=3F...................................(4)

Substituting equations (2) and (4) into eqn (3)

-9F+10F=1

F = 1

Put the value of F into equations (2) and (4)

E = -2(1) = -2

D = 3(1) = 3

Substituting the values of D, E, and F into (*)

U = t² = 3 [1 − 3t²] - 2 [2+t− 5t²] + [1 + 2t]

3 0
3 years ago
8.4 gallons of gas for $23.94. Which equation can be used to determine the price of each gallon of gas?
mojhsa [17]
Here is the equation: (gas=g)

8.5g= 23.94

All you need to do is the inverse of multiplication on the other side. (division)

23.94/8.5= 2.81647.....

g= 2.82 (rounded to the hundredths place)

I hope this helps!
~kaikers
6 0
3 years ago
How do we convert kilogram to gram​
Sloan [31]

<u>1kg=1000g</u>

7kg*1000=7000g

10kg*1000=10000g

15g*1000=15000g

5 0
3 years ago
Please I need help asap
andrey2020 [161]

Answer:

Option D

Step-by-step explanation:

\frac{2}{3}x=\frac{12}{5}

x=(\frac{12}{5} )(\frac{3}{2} )=\frac{36}{10} =\frac{18}{5} =3\frac{3}{5}

Hope this helps

6 0
2 years ago
Evaluate the expression
larisa86 [58]

Answer:

12-[20-2(6^2\div3\times2^2)]=88

Step-by-step explanation:

So we have the expression:

12-[20-2(6^2\div3\times2^2)]

Recall the order of operations or PEMDAS:

P: Operations within parentheses must be done first. On a side note, do parentheses before brackets.

E: Within the parentheses, if exponents are present, do them before all other operations.

M/D: Multiplication and division next, whichever comes first.

A/S: Addition and subtraction next, whichever comes first.

(Note: This is how the order of operations is traditionally taught and how it was to me. If this is different for you, I do apologize. However, the answer should be the same.)

Thus, we should do the operations inside the parentheses first. Therefore:

12-[20-2(6^2\div3\times2^2)]

The parentheses is:

(6^2\div3\times2^2)

Square the 6 and the 4:

(36\div3\times4)

Do the operations from left to right. 36 divided by 3 is 12. 12 times 4 is 48:

(36\div3\times4)\\=(12\times4)\\=48

Therefore, the original equation is now:

12-[20-2(6^2\div3\times2^2)]\\=12- [20-2(48)]

Multiply with the brackets:

=12-[20-96]

Subtract with the brackets:

=12-[-76]

Two negatives make a positive. Add:

=12+76=88

Therefore:

12-[20-2(6^2\div3\times2^2)]=88

3 0
3 years ago
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