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Alinara [238K]
2 years ago
13

Globes that were once selling for $20 are now selling for $7. what percentage is the discount​

Mathematics
1 answer:
Zina [86]2 years ago
4 0

Answer:

35%

Step-by-step explanation:

7/20 = 0.35

please mark brainliest

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I’m not sure which one it is.
Fofino [41]

Answer: the answer is A) AC~=FC

Step-by-step explanation:

to answer that both triangles are congruent using SSS (Side-side-side) postulate, you have to show that each corresponding side is the same.

4 0
2 years ago
Given the box plot, will the mean or the median provide a better description of the center? box plot with min at 11, Q1 at 22. 5
Slav-nsk [51]

The median, because the data distribution is skewed to the right.

Given that

The box plot with the following parameters:  

Minimum value at 11,

First Quartile, Q1 at 22.5,

Median at 34.5,

Third Quartile, Q3 at 36,

Maximum value at 37.5.

According to the question

When a distribution has a longer tail to one of its sides, then it is said to be skewed.

Since the tail is longer to the left, it is said to be left-skewed.

The data distribution is skewed to the left because the median (34.5) is closer to the third quartile (36) than to the first quartile  (22.5).

For skewed data, we always prefer the median because it is less affected by the outliers and if the mean is chosen, the value of the mean is biased towards the side that has larger values while the median does not get affected by it. So, we choose the median.

For skewed distributions, the median is the best measure of center.

Hence, the median, because the data distribution is skewed to the right.

To know more about Mean click the link given below.

brainly.com/question/2508120

3 0
2 years ago
A high school as the department that 40 soccer uniforms at a cost of $3000 after soccer season they return some of the uniform i
love history [14]

$3000 divided by 40 = 75...Mark as brainliest.......
6 0
3 years ago
Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1
sleet_krkn [62]

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}

From Left side:

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)

\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}

NOTE: sin²θ + cos²θ = 1

\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{2}{sin^2\theta-cos^2\theta}

\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}

\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}

\dfrac{2sec^2\theta}{tan^2\theta-1}

Left side = Right side <em>so proof is complete</em>

8 0
3 years ago
Read 2 more answers
Jessica is asked to write a quadratic equation to represent a function that goes through the point (8, –11) and has a vertex at
Kitty [74]

Answer: c

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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