Can someone please help me out with this problem please

Ashley deposits $10 000 at the end of each month for 6 times at rate of 5% compounded monthly. How much will be in her account

xz_007 [3.2K]

The future values of Ashley's periodic deposits under the five scenarios are stated in the deposit table as follows:

<h3>Deposit Table:</h3>

Item Initial Periodic Deposit Interest Future Value Interest

Deposit Deposit Period Rate ($)

a. $10,000 $10,000 6 months 5% $61,774.51 $1,774.51

b. $10,000 $10,000 3 months 5% $30,502.78 $502.78

c. $10,000 $10,000 6 months 5% $51,774.51 $1,522.42

d. $20,000 $10,000 6 months 5% $72,201.71 $2,201.71

e. $10,000 $10,000 6 months 5%/6% $60,803.78 $803.78

<h3>What is the future value?</h3>

The future value of a periodic investment represents the present value of cash flows compounded at an interest rate into the future.

The future value is computed using the FV formula or factor.

It can also be computed using an online finance calculator as follows:

<h3>Data and Calculations:</h3>

Periodic Deposit = $10,000

Investment period = 6 months

Interest rate = 5% compounded monthly

<h3>a) for illustration:</h3>

N (# of periods) = 6 months

I/Y (Interest per year) = 5%

PV (Present Value) = $0

PMT (Periodic Payment) = $10,000

<u>Results</u>:

FV = $61,774.51

Sum of all periodic payments = $60,000 ($10,000 x 6)

Total Interest = $1,774.51

<h3>Other Special Cases:</h3>

c) Interest on $10,000 for 3 months is $1,522.42 ($1,774.51 - $252.09).

d) Future Value Interest

5% with $20,000 $82,285.04 $2,285.04

5% with $10,000 (10,083.33) (83.33)

Total for 6 months $72,201.71 $2,201.71

e) Future Value Interest

5% for 3 months $30,502.78 $502.78

6% for 3 months $30,301.00 $301.00

Total for 6 months $60,803.78 $803.78

Learn more about the computation of future values at brainly.com/question/24703884 and brainly.com/question/12979998

#SPJ1

4 0

1 year ago

Can someone explain to me what a “derivative” means? How do you find the derivative of f(x)=x^3+1?

Ostrovityanka [42]

The derivative is the rate of change of a function, basically represents the slope at different points. To find the derivative of the given function you can use the power rule, which means, if n is a real number, d/dx(x^n)= nx^(n-1). This is a simplification of the chain rule based on the fact that d/dx(x)=1. Anyway, this means that d/dx(x^3 + 1)= 3x^2. Here n is 3 and so it is 3*x^(3-1)= 3x^2. The derivative of x^3+1 is 3x^2.

If you are wondering what happened to the 1, for any constant C, d/dx(C)=0.

4 0

3 years ago

Find x, given that ΔABE ~ ΔBCD.

SIZIF [17.4K]

X = 9 . Basically just divide 12 by 8 and then take that quotient (1.5) and multiply it by 6 in order to receive the product of 9.
Hope this helps! :)

3 0

2 years ago

Shawna is a member of the swim team. She can swim 3 laps in 3 minutes

likoan [24]

Answer:

8 mins 56 secs

Step-by-step explanation:

3 minutes and 21 seconds divided by 3 laps is 1.07 so it takes her 1 minute and 0.7 sec for each lap then u just multuply 1.07 by 8 and u get 8.56 meaning 8 mins and 56 secs. hope i helped :)

6 0

2 years ago

he amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and s

sp2606 [1]

Complete question:

He amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and standard deviation 1.4 minutes. Suppose that a random sample of n equals 47 customers is observed. Find the probability that the average time waiting in line for these customers is

a) less than 8 minutes

b) between 8 and 9 minutes

c) less than 7.5 minutes

Answer:

a) 0.0708

b) 0.9291

c) 0.0000

Step-by-step explanation:

Given:

n = 47

u = 8.3 mins

s.d = 1.4 mins

a) Less than 8 minutes:

$P(X$

P(X' < 8) = P(Z< - 1.47)

Using the normal distribution table:

NORMSDIST(-1.47)

= 0.0708

b) between 8 and 9 minutes:

P(8< X' <9) = $[\frac{8-8.3}{1.4/ \sqrt{47}}< \frac{X'-u}{s.d/ \sqrt{n}} < \frac{9-8.3}{1.4/ \sqrt{47}}]$

= P(-1.47 <Z< 6.366)

= P( Z< 6.366) - P(Z< -1.47)

Using normal distribution table,

$NORMSDIST(6.366)-NORMSDIST(-1.47)$

0.9999 - 0.0708

= 0.9291

c) Less than 7.5 minutes:

P(X'<7.5) = $P [Z< \frac{7.5-8.3}{1.4/ \sqrt{47}}]$

P(X' < 7.5) = P(Z< -3.92)

NORMSDIST (-3.92)

= 0.0000

3 0

2 years ago

Can someone please help me out with this problem please ​

Can someone please help me out with this problem please