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3 years ago

What exactly are prime numbers?

2 answers:

6 0

Prime numbers are numbers that are greater than one and its only factors, the things that multiply to equal it, are one and itself. An example is the number seven the only numbers multiplied together that can equal 7 are 7x1.

nignag [31]3 years ago

4 0

Prime numbers are numbers that only have a factor of one and its self.

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Nathan opens a new savings account and makes an initial deposit of $400.

AfilCa [17]

Answer:

The answer to the first one is 6

Step-by-step explanation:

If the time frame given is 9 months, then we can find that 9 months is 3/4 of a year. 3/4 x 2% = 0.015. 0.015 x 400 = 6. He would have made 6 dollars in 9 months.

Answer the the second one:

4.5% x 5 (years) = 0.225. 0.225 x 10,000 = 2,250. Since this is a car loan and not a bank interest for example, we add it to the total cost. I'm pretty sure its the third one.

6 0

3 years ago

Express the product of (1/5x + 1) and (1/6x + 5/4) as a trinomial in simplest form

Greeley [361]

$(\frac{1}{5}x+1)(\frac{1}{6}x+\frac{5}{4})$

Use distributive property to remove the parentheses:

$(a+b)(c+d)=ac+ad+bc+bd$ $\begin{gathered} =\frac{1}{5}x*\frac{1}{6}x+\frac{1}{5}x*\frac{5}{4}+1*\frac{1}{6}x+1*\frac{5}{4} \\ \\ Multiplication\text{ }of\text{ }fractions: \\ \frac{a}{b}*\frac{c}{d}=\frac{a*c}{b*d} \\ \\ =\frac{1}{30}x^2+\frac{5}{20}x+\frac{1}{6}x+\frac{5}{4} \\ \\ =\frac{1}{30}x^2+\frac{1}{4}x+\frac{1}{6}x+\frac{5}{4} \\ \\ Addition\text{ }of\text{ }fractions: \\ \frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd} \\ \\ =\frac{1}{30}x^2+(\frac{6x+4x}{24})+\frac{5}{4} \\ \\ =\frac{1}{30}x^2+\frac{10}{24}x+\frac{5}{4} \\ \\ Simplify: \\ =\frac{1}{30}x^2+\frac{5}{12}x+\frac{5}{4} \end{gathered}$ Then, the product in the simplest form is: $\frac{1}{30}x^2+\frac{5}{12}x+\frac{5}{4}$

8 0

1 year ago

In right triangle ABC shown below, what is the degree measure of ZC ?

Luden [163]

Answer:

90+30=120

180-120=60 this is degree measure

4 0

3 years ago

A real estate agent has 8 master keys to open several new homes. Only 1 master key will open any given house. If 40% of these ho

riadik2000 [5.3K]

Answer:

Step-by-step explanation:

Suppose F represents the value that a room is unlocked.

Then, we can assume that the probability of unlocked homes is:

P(unlocked homes) = P(U)

P(unlocked homes) = 40%

P(unlocked homes) = 0.40

Also, let us represent the value of the locked room with G.

P(locked homes) = P(G)

P(locked homes) = (1 - 0.40)

P(locked homes) = 0.60

Let the probability of selecting a correct key be P(S)

It implies that for the agent to use 3 keys, we have a combination of $^8C_3$ possible ways for the set of keys.

Now; since only one will open the house, then:

P(select correct key) = P(S)

$P(S) = \dfrac{ (^1_1) (^7_2) }{ ^8_3 }$

$P(S) = \dfrac{21}{56}$

P(S) = 0.375

Finally, for the real estate agent to have access to specific homes supposing the agent select three master keys at random prior to the time he left his office, Then:

P(F ∪ (G∩S) = P(F) + P(G∩S)

P(F ∪ (G∩S) = P(F) + P(G) × P(S)

P(F ∪ (G∩S) = 0.40 + (0.60×0.375)

P(F ∪ (G∩S) = 0.40 + 0.225

P(F ∪ (G∩S) =0.625

5 0

2 years ago

When running a 100 meter race Bill reaches his maximum speed when he is 45 meters from the starting line and 5 seconds have elap

Mkey [24]

Bill's speed is constant after 5 seconds and 45 meters into the race.

Correct responses:

a. Bill's maximum speed is 8 m/s

b. 24 meters

c. 57 meters

<h3>Methods used to calculate speed and distance traveled</h3>

Given parameters are;

The distance of the race = 100 meter

Distance at which Bill reaches maximum speed = 45 meters

Speed Bill maintains after 5 seconds = The maximum speed

Time at which Bill is 85 meters from the starting line = 10 seconds after start

a. Required;

Bill's maximum speed in meters.

Solution:

Distance Bill runs at maximum speed, d = 85 m - 45 m = 40 m

Time at which Bill runs the 40 m at maximum speed, t = 10 s - 5 s = 5 s

$Speed = \mathbf{\dfrac{Distance}{Time}}$

Therefore;

$Bill's \ maximum \ speed = \dfrac{40 \ m}{5 \ s} = \underline{8 \ m/s}$

b. i. Required:

The distance Bill will run for 3 seconds at the maximum speed;

Solution:

Distance, s = Speed, v × Time, t

The distance traveled at maximum speed in 3 seconds is therefore;

Distance = 8 m/s × 3 s = 24 m

The distance Bill travels in 3 seconds at the maximum speed is 24 meters.

ii) The distance Bill travels at 8 seconds after start, is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 3 seconds = 24 meters

Therefore;

Bill's distance from the starting line 8 seconds after start is 45 meters + 25 meters = 69 meters

c. Bill's distance 6.5 seconds after the start of the race is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 1.5 seconds = 1.5 s × 8 m/s = 12 meters

Bill's distance from the starting line 6.5 seconds after start of the race = 45 meters + 12 meters = 57 meters

Learn more about distance, speed, time, relationship here:

https://brainly.in/question/49075584

6 0

2 years ago